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Maths-

General

Easy

Question

Solve $fraction numerator 6 x plus 8 over denominator 2 end fraction$ - 4 = 3x

hint Hint:

An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained.

The correct answer is: The given system of equations have infinitely many solutions.

Step-by-step solution:-
$fraction numerator 6 x plus 8 over denominator 2 end fraction$ - 4 = 3x
∴ $fraction numerator 6 x plus 8 over denominator 2 end fraction$ = 3x + 4 ........................ (Adding 4 both the sides)
∴ 6x + 8 = 6x + 8 ...................... (Multiplying both sides by 2)
∴ 6x - 6x = 8 - 8
∴ 0 = 0
Since, LHS = RHS the given set of equations are identical and hence, has infinitely many solutions. i.e. for any value of x, the given equation will be satisfied.
Final Answer:-
∴ The given system of equations have infinitely many solutions.

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