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Mathematics

Grade10

Easy

Question

Solve the following using the substitution method and find the value of x and y:
5x – 2y = -4
-5x + 4y = 8

0, 1
1, 0
-1, 0
0, 2

hint Hint:

To find the value of x and y from the given two equations from substituting method we need to find y first in the terms of x from equation 1 and then use the value of y in equatin 2, we will get x then we will put the value of x in y to get y.

The correct answer is: 0, 2

5x – 2y = -4 (equation 1)
-5x + 4y = 8 (equation 2)
-2y = -4 – 5x (from equation 1)
y = $fraction numerator negative 4 minus 5 m over denominator negative 2 end fraction$
y = $fraction numerator 5 m plus 4 over denominator 2 end fraction$
substituting value of y in equation 2,
-5x + 4y = 8
-5x + 4 $open parentheses fraction numerator 5 m plus 4 over denominator 2 end fraction close parentheses$ = 8
-5x + $fraction numerator 20 m plus 16 over denominator 2 end fraction$ = 8
$fraction numerator negative 10 x plus 20 x plus 16 over denominator 2 end fraction$ = 8
10x + 16 = 16
10x = 0
x = 0
putting value of x in y,
5(0) - 2y = -4
-2y = -4
y = 2

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