Mathematics
Grade10
Easy

Question

Solve the following using the substitution method and find the value of x and y:
-5x + 3y = -22
-5x + y = -24

  1. 5, 1
  2. 5, 2
  3. 5, 3
  4. 5, 9

Hint:

The linear equation in two variable is an equation with two variable and degree one.

The correct answer is: 5, 1


    Step 1 of 1:
    We have given two equations
    -5x + 3y = -22....(i)
    -5x + y = -24......(ii)
    Rewrite first equation and then substitute
    3y = 5x – 22
    y= fraction numerator 5 x minus 22 over denominator 3 end fraction
    Now substitute the value of y in 2nd equation.
    negative 5 x space plus fraction numerator 5 x minus 22 over denominator 3 end fraction = -24
    fraction numerator negative 15 x plus 5 x minus 22 over denominator 3 end fraction = -24
    -10x – 22 = -72
    -10x = -50
    x = 5
    Now put the value of x in 2nd equation
    -5(5) + y = -24
    y = -24 + 25
    =1

    In the substitution method, we first write one variable in the form of another variable.

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