Maths-

General

Easy

Question

# Solve the system of equations by elimination :

10X + 6Y = 38

10X + 20Y = 100

## The correct answer is: x=8/7 and y=31/7

### SOLUTION:

HINT: Perform any arithmetic operation and then find.

Complete step by step solution:

Let 10x + 6y = 38…(i)

and 10x + 20y = 100….(ii)

Now, we have the coefficients of x in (i) and (ii) to be the same.

On subtracting (i) from (ii),

we get LHS to be 10x + 20y - (10x + 6y) = 20y - 6y = 14y

and RHS to be 100 - 38 = 62

On equating LHS and RHS, we have 14y = 62

On substituting the value of y in (i), we get

Hence we get

Note: We can also solve these system of equations by making the coefficients of y

to be the same in both the equations

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