Maths-

General

Easy

Question

# Solve the system of equations by elimination :

5X + 3Y = 19

2X + 4Y = 20

Hint:

**HINT:** Perform any arithmetic operation and then find.

## The correct answer is: x=8/7 and y=31/7

### Complete step by step solution:

Let 5x + 3y = 19…(i)

and 2x + 4y = 20….(ii)

On multiplying (i) with 2, we get 2(5x + 3y = 19)

⇒10x + 6y = 38…(iii)

On multiplying (ii) with 5, we get 5(2x + 4y = 20)

⇒10x + 20y = 100…(iv)

Now, we have the coefficients of x in (iii) and (iv) to be the same.

On subtracting (iii) from (iv),

we get LHS to be 10x + 20y - (10x+ 6y) = 20y - 6y = 14y

and RHS to be 100 - 38 = 62

On equating LHS and RHS, we have 14y = 62

On substituting the value of y in (i), we get

Hence we get

Note: We can also solve these system of equations by making the coefficients of y

to be the same in both the equations

Hence we get

Note: We can also solve these system of equations by making the coefficients of y

to be the same in both the equations

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