Question

Statement 1:Oxidation number of Ni in is zero.

Statement 2:Nickel is bonded to neutral ligand carbonyl.

- Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1
- Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1
- Statement 1 is True, Statement 2 is False
- Statement 1 is False, Statement 2 is True

## The correct answer is: Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1

### Related Questions to study

Suppose equation is f(x) – g(x) = 0 of f(x) = g(x) = y say, then draw the graphs of y = f(x) and y = g(x). If graph of y = f(x) and y = g(x) cuts at one, two, three, ...., no points, then number of solutions are one, two, three, ...., zero respectively.

The number of solutions of sin x = is

In this question, we have drawn the graph. The number of intersections of both function fx and gx are the number solutions. Draw the graph carefully and find the intersection points.

Suppose equation is f(x) – g(x) = 0 of f(x) = g(x) = y say, then draw the graphs of y = f(x) and y = g(x). If graph of y = f(x) and y = g(x) cuts at one, two, three, ...., no points, then number of solutions are one, two, three, ...., zero respectively.

The number of solutions of sin x = is

In this question, we have drawn the graph. The number of intersections of both function fx and gx are the number solutions. Draw the graph carefully and find the intersection points.

The first noble gas compound obtained was:

The first noble gas compound obtained was:

### Statement 1:The redox titrations in which liberated is used as oxidant are called as iodometric titrations

Statement 2:Addition of KI of liberates which is estimated against hypo solution.

### Statement 1:The redox titrations in which liberated is used as oxidant are called as iodometric titrations

Statement 2:Addition of KI of liberates which is estimated against hypo solution.

### molecule is completely changed into molecules at:

### molecule is completely changed into molecules at:

Statement-I : If and then

Statement-II : If sinA = sinB and cosA = cosB, then

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, Start solving first Statement and try to prove it. Then solve the Statement-II.

Statement-I : If and then

Statement-II : If sinA = sinB and cosA = cosB, then

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, Start solving first Statement and try to prove it. Then solve the Statement-II.

Arsine is:

Arsine is:

Statement-I : The equation sin(cos x) = cos(sin x) does not possess real roots.

Statement-II : If sin x > 0, then

Statement-I : The equation sin(cos x) = cos(sin x) does not possess real roots.

Statement-II : If sin x > 0, then

Statement-I : In (0, ), the number of solutions of the equation is two

Statement-II : is not defined at

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, it has 5 solutions, but tanθ &tan3θ are not defined at , , . respectively so it remains only 2.

Statement-I : In (0, ), the number of solutions of the equation is two

Statement-II : is not defined at

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, it has 5 solutions, but tanθ &tan3θ are not defined at , , . respectively so it remains only 2.

Statement-I : If sin x + cos x = then

Statement-II : AM ≥ GM

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, Start solving first Statement and try to prove it. Then solve the Statement-II. Always, the AM–GM inequality states that AM ≥ GM.

Statement-I : If sin x + cos x = then

Statement-II : AM ≥ GM

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, Start solving first Statement and try to prove it. Then solve the Statement-II. Always, the AM–GM inequality states that AM ≥ GM.

Statement-I : The number of real solutions of the equation sin x = 2^{x} + 2^{–x} is zero

Statement-II : Since |sin x| ≤ 1

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, -1 ≤ sinx ≤ 1 for all value, remember that.

Statement-I : The number of real solutions of the equation sin x = 2^{x} + 2^{–x} is zero

Statement-II : Since |sin x| ≤ 1

In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, -1 ≤ sinx ≤ 1 for all value, remember that.

### if

### if

### if

### if

### if

### if

### if

### if

### if

In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.

### if

In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.