Question

# Statement 1:The reaction between and occurs in an acidic medium

Statement 2: is reduced to in acidic medium

- Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1
- Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1
- Statement 1 is True, Statement 2 is False
- Statement 1 is False, Statement 2 is True

## The correct answer is: Statement 1 is False, Statement 2 is True

### Related Questions to study

Number of cyphers after decimal before a significant figure comes in is

In this question, we have to find the number of cyphers. We need to remember that the cypher number can be found from the logarithmic calculation but to find the actual value or to visualize it we need to remove the logarithm. Here, log_{10}5 = 0.6990 and log_{10}3 = 0.4770.

Number of cyphers after decimal before a significant figure comes in is

In this question, we have to find the number of cyphers. We need to remember that the cypher number can be found from the logarithmic calculation but to find the actual value or to visualize it we need to remove the logarithm. Here, log_{10}5 = 0.6990 and log_{10}3 = 0.4770.

The value of p for which both the roots of the quadratic equation, are less than 2 lies in :

In this question, we have to find where the p lies. Here, we use discriminant, which is . if D > 0 and D = 0 then real solution but if D < 0 then imaginary solution. Here we also us Factorization of quadratic equations.

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In this question, we have to find where the p lies. Here, we use discriminant, which is . if D > 0 and D = 0 then real solution but if D < 0 then imaginary solution. Here we also us Factorization of quadratic equations.

### If where determine b –

Just like we can change the base b for the exponential function, we can also change the base b for the logarithmic function. The logarithm with base b is defined so that

### If where determine b –

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### Statement 1:The two Fe atoms in have different oxidation numbers

Statement 2: ions decolourise solution

### Statement 1:The two Fe atoms in have different oxidation numbers

Statement 2: ions decolourise solution

### , where and is

In this question, we have to find the . Here Solve first B. In B, rationalize it means multiply it denominator by sign change in both numerator and denominator

### , where and is

In this question, we have to find the . Here Solve first B. In B, rationalize it means multiply it denominator by sign change in both numerator and denominator

Statement 1:The equivalence point refers the condition where equivalents of one species react with same number of equivalent of other species.

Statement 2:The end point of titration is exactly equal to equivalence point

Statement 1:The equivalence point refers the condition where equivalents of one species react with same number of equivalent of other species.

Statement 2:The end point of titration is exactly equal to equivalence point

If and are the roots of the equation then the value of equals

If and are the roots of the equation then the value of equals

Statement 1:Iodimetric titration are redox titrations.

Statement 2:The iodine solution acts as an oxidant to reduce the reductant

Statement 1:Iodimetric titration are redox titrations.

Statement 2:The iodine solution acts as an oxidant to reduce the reductant

Statement 1:Diisopropyl ketone on reaction with isopropyl magnesium bromide followed by hydrolysis gives alcohol

Statement 2:Grignard reagent acts as a reducing agent

Statement 1:Diisopropyl ketone on reaction with isopropyl magnesium bromide followed by hydrolysis gives alcohol

Statement 2:Grignard reagent acts as a reducing agent

The first noble gas compound obtained was:

The first noble gas compound obtained was:

Given that and then value of equals –

These four basic properties all follow directly from the fact that logs are exponents.

log_{b}(*xy*) = log_{b}*x* + log_{b}*y*.

log_{b}(*x/y*) = log_{b}*x* - log_{b}*y*.

log_{b}(*x ^{n}*) =

*n*log

_{b}

*x*.

log

_{b}

*x*= log

_{a}

*x*/ log

_{a}

*b*.

Given that and then value of equals –

These four basic properties all follow directly from the fact that logs are exponents.

log_{b}(*xy*) = log_{b}*x* + log_{b}*y*.

log_{b}(*x/y*) = log_{b}*x* - log_{b}*y*.

log_{b}(*x ^{n}*) =

*n*log

_{b}

*x*.

log

_{b}

*x*= log

_{a}

*x*/ log

_{a}

*b*.

Statement 1:Change in colour of acidic solution of potassium dichromate by breath is used to test drunk drivers.

Statement 2:Change in colour is due to the complexation of alcohol with potassium dichromate.

Statement 1:Change in colour of acidic solution of potassium dichromate by breath is used to test drunk drivers.

Statement 2:Change in colour is due to the complexation of alcohol with potassium dichromate.

Total number of solutions of sin{x} = cos{x}, where {.} denotes the fractional part, in [0, 2] is equal to

In this question, we have to find the number of solutions. Here we have fractional part of x. It is {x} and {x}= x-[x]. The {x} is always belongs to 0 to 1.

Total number of solutions of sin{x} = cos{x}, where {.} denotes the fractional part, in [0, 2] is equal to

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Statement 1:If a strong acid is added to a solution of potassium chromate it changes itscolour from yellow to orange.

Statement 2:The colour change is due to the oxidation of potassium chromate.

Statement 1:If a strong acid is added to a solution of potassium chromate it changes itscolour from yellow to orange.

Statement 2:The colour change is due to the oxidation of potassium chromate.

Total number of solutions of the equation 3x + 2 tan x = in x [0, 2] is equal to

In this question, we use the graph of tanx . The intersection is the total number of solutions of this equation. The graph region is [ 0, 2π ].

Total number of solutions of the equation 3x + 2 tan x = in x [0, 2] is equal to

In this question, we use the graph of tanx . The intersection is the total number of solutions of this equation. The graph region is [ 0, 2π ].