Maths-
General
Easy

Question

The angle of rotation of axes in order to eliminate xy term of the equation x squared plus 2 square root of 3 x y minus y squared equals 2 a squared is

  1. pi over 6
  2. pi over 4
  3. pi over 3
  4. pi over 2

hintHint:

Find the rotation of the equation and then find the angle.

The correct answer is: pi over 6


    Given That:
    >>> Let the angle of rotation of axes be ϕ and let the new coordinates be x and y.
    >>> Thus, the old coordinates are:-
                   x xcosϕysinϕx   =  x to the power of prime cos invisible function application ϕ minus y to the power of prime sin invisible function application ϕ
                   y xsinϕ+ycosϕy   =  x to the power of prime sin invisible function application ϕ plus y to the power of prime cos invisible function application ϕ
    >>> Now, we will put the value of coordinates in the given equation 
    We know from the trigonometric identities that
    cos2ϕsin2ϕ=cos2ϕnot stretchy rightwards double arrow cos to the power of 2 end exponent ϕ minus sin to the power of 2 end exponent ϕ equals cos invisible function application 2 ϕ and2cosϕsinϕ=sin2ϕ2 cos invisible function application ϕ sin invisible function application ϕ equals sin invisible function application 2 ϕ

    >>> On further simplifying the terms, we get:
    >>> ⇒tan2ϕ=square root of 3
    >>> Therefore, the value of ϕis:-
    not stretchy rightwards double arrow 2ϕ=straight pi over 3
    not stretchy rightwards double arrow ϕ=straight pi over 6

    >>> Hence, the required angle of rotation of axes is straight pi over 6

    The Angle of rotation becomes straight pi over 6

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