General
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Chemistry-

The characteristic group of secondary alcohol is:

Chemistry-General

    Answer:The correct answer is: General formula for alcohols is C subscript n H subscript left parenthesis 2 n plus 1 right parenthesis O H Primary alcohols have negative C H subscript 2 O H g p .Secondary

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    General
    chemistry-

    Primary amine on treatment with N a N O subscript 2 a n d space H C l space yields:

    Primary amine on treatment with N a N O subscript 2 a n d space H C l space yields:

    chemistry-General
    General
    chemistry-

    Phenol on treatment with diethyl sulphate in presence of N a O H spacegives

    Diethyl sulphate in the presence of NaOH acts as alkylating agent, it causes alkylation of phenol to give ethyl phenyl ether which is also called phenetole.C subscript 6 H subscript 5 O H plus N a O H rightwards arrow C subscript 6 H subscript 5 O to the power of minus N a to the power of plus plus H subscript 2 O 

    Phenol on treatment with diethyl sulphate in presence of N a O H spacegives

    chemistry-General
    Diethyl sulphate in the presence of NaOH acts as alkylating agent, it causes alkylation of phenol to give ethyl phenyl ether which is also called phenetole.C subscript 6 H subscript 5 O H plus N a O H rightwards arrow C subscript 6 H subscript 5 O to the power of minus N a to the power of plus plus H subscript 2 O 
    General
    chemistry-

    Alcoholic beverages contain

    Alcoholic beverages contain

    chemistry-General
    General
    chemistry-

    Product is

    Product is

    chemistry-General
    General
    chemistry-

    Ethyl iodide on treatment with dry  A g subscript 2 O will yield:

    2 C subscript 2 H subscript 5 I plus left parenthesis A g subscript 2 O right parenthesis ┬ E t h e r ⟶ C subscript 2 H subscript 5 O C subscript 2 H subscript 5

    Ethyl iodide on treatment with dry  A g subscript 2 O will yield:

    chemistry-General
    2 C subscript 2 H subscript 5 I plus left parenthesis A g subscript 2 O right parenthesis ┬ E t h e r ⟶ C subscript 2 H subscript 5 O C subscript 2 H subscript 5
    General
    maths-

    If X is a square matrix of order 3 × 3 and lambda is a scalar, then adj (lambda X right parenthesis is equal to

    By fundamental property, a d j left parenthesis lambda X right parenthesis equals lambda to the power of n minus 1 end exponent left parenthesis a d j X right parenthesis.
    Here n equals 3
    \a d j left parenthesis lambda X right parenthesis equals lambda to the power of 3 minus 1 end exponent left parenthesis a d j X right parenthesis
    a d j left parenthesis lambda X right parenthesis equals lambda to the power of 2 end exponent left parenthesis a d j X right parenthesis.

    If X is a square matrix of order 3 × 3 and lambda is a scalar, then adj (lambda X right parenthesis is equal to

    maths-General
    By fundamental property, a d j left parenthesis lambda X right parenthesis equals lambda to the power of n minus 1 end exponent left parenthesis a d j X right parenthesis.
    Here n equals 3
    \a d j left parenthesis lambda X right parenthesis equals lambda to the power of 3 minus 1 end exponent left parenthesis a d j X right parenthesis
    a d j left parenthesis lambda X right parenthesis equals lambda to the power of 2 end exponent left parenthesis a d j X right parenthesis.
    General
    chemistry-

    Phenol not stretchy rightwards arrow with X on top forms a tribromo derivative “X ” is

    Phenol not stretchy rightwards arrow with X on top forms a tribromo derivative “X ” is

    chemistry-General
    General
    physics-

    The effective focal length of the lens combination shown in figure is - 60 cm The radii of curvature of the curved surfaces of the plano-convex lenses are 12 cm each and refractive index of the material of the lens is 1.5 The refractive index of the liquid is

    The effective focal length of the lens combination shown in figure is - 60 cm The radii of curvature of the curved surfaces of the plano-convex lenses are 12 cm each and refractive index of the material of the lens is 1.5 The refractive index of the liquid is

    physics-General
    General
    physics-

    A ray of ligth enters into a glass slab from air as shown .If refractive of glass slab is given by mu equals A minus B t where A and B are constants and ‘t’ is the thickness of slab measured from the top surface Find the maximum depth travelled by ray in the slab Assume thickness of slab to be sufficiently large

    A ray of ligth enters into a glass slab from air as shown .If refractive of glass slab is given by mu equals A minus B t where A and B are constants and ‘t’ is the thickness of slab measured from the top surface Find the maximum depth travelled by ray in the slab Assume thickness of slab to be sufficiently large

    physics-General
    General
    physics-

    The refraction index of an anisotropic medium varies as mu equals mu subscript 0 end subscript square root of left parenthesis x plus left parenthesis A right parenthesis end root comma text  where  end text 0 less or equal than x less or equal than aA ray of light is incident at the origin just along y-axis (shown in figure) Find the equation of ray in the medium

    The refraction index of an anisotropic medium varies as mu equals mu subscript 0 end subscript square root of left parenthesis x plus left parenthesis A right parenthesis end root comma text  where  end text 0 less or equal than x less or equal than aA ray of light is incident at the origin just along y-axis (shown in figure) Find the equation of ray in the medium

    physics-General
    General
    physics-

    Due to a vertical temperature gradient in the atmosphere, the index of refraction varies Suppose index of refraction varies as n equals n subscript 0 end subscript square root of 1 plus a y end root comma text  where  end text n subscript 0 end subscript is the index of refraction at the surface and a equals 2.0 cross times 10 to the power of negative 6 end exponent m to the power of negative 1 end exponent A person of height h = 2.0 m stands on a level surface Beyond what distance will he not see the runway?

    Due to a vertical temperature gradient in the atmosphere, the index of refraction varies Suppose index of refraction varies as n equals n subscript 0 end subscript square root of 1 plus a y end root comma text  where  end text n subscript 0 end subscript is the index of refraction at the surface and a equals 2.0 cross times 10 to the power of negative 6 end exponent m to the power of negative 1 end exponent A person of height h = 2.0 m stands on a level surface Beyond what distance will he not see the runway?

    physics-General
    General
    physics-

    Find the variation of refractive index assuming it to be a function of y such that a ray entering origin at grazing incidence follows a parabolic path y = x2 as shown in fig

    Find the variation of refractive index assuming it to be a function of y such that a ray entering origin at grazing incidence follows a parabolic path y = x2 as shown in fig

    physics-General
    General
    chemistry-

    Metal oxides which decomposes on heating is

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    Metal oxides which decomposes on heating is

    chemistry-General
    Error converting from MathML to accessible text.
    General
    chemistry-

    One mole of an organic compound A with the formula C subscript 3 H subscript 8 O reacts completely with two moles of HI to form X and Y. When Y is boiled with aqueous alkali it forms Z. Z answers the iodoform test. The compound A is

    Molecular formula C subscript 3 H subscript 8 O open parentheses C subscript n H subscript 2 n plus 2 end subscript O close parentheses suggests that the organic compound is either alcohol or ether. Since, the compound on reaction with HI gives two different compounds, It must be an unsymmetrical ether, and its formula must be C H subscript 3 O C subscript 2 H subscript 5 (methoxyethane). 

    One mole of an organic compound A with the formula C subscript 3 H subscript 8 O reacts completely with two moles of HI to form X and Y. When Y is boiled with aqueous alkali it forms Z. Z answers the iodoform test. The compound A is

    chemistry-General
    Molecular formula C subscript 3 H subscript 8 O open parentheses C subscript n H subscript 2 n plus 2 end subscript O close parentheses suggests that the organic compound is either alcohol or ether. Since, the compound on reaction with HI gives two different compounds, It must be an unsymmetrical ether, and its formula must be C H subscript 3 O C subscript 2 H subscript 5 (methoxyethane). 
    General
    physics-

    A reflecting surface is represented by the equation x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent A ray travelling in negative x-direction is directed towards positive y-direction after reflection from the surface at point P Then co-ordinates of point P are

    A reflecting surface is represented by the equation x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent A ray travelling in negative x-direction is directed towards positive y-direction after reflection from the surface at point P Then co-ordinates of point P are

    physics-General