The cross section of a concrete wall to be constructed . it is 3 m wide at the top 5.5 m wide at the bottom and its height is 10 m and its length is 500 m , Calculate the volume of the concrete in wall ?

The correct answer is: Volume of the concrete in the wall is 21,250 m3.

Step-by-step solution:
From the adjacent diagram we can observe that the given wall is made up of two parts i.e. Rectangular (Cuboidal) part and the triangular part.

We will calculate the volume of each part separately and add the same to find the column of the entire wall.
For the rectangular part-

• Length = 500 m
• Breadth = 3 m
• Height = 10m

∴ Volume of the Rectangular (Cubaoidal) part = length breadth height
∴ Volume of the Rectangular (Cubaoidal) part = 500 3 10
∴ Volume of the Rectangular (Cubaoidal) part = 15,000 ................................ (Equation i)
For the triangular part-
Base = 2.5m (5.5m - 3m)
Height = 10m
Volume of the entire triangular part = Area of the triangular face Length of the wall.
∴ Volume of the entire triangular part = (1/2 base height) 500
∴ Volume of the entire triangular part = (1/2 2.5 10) 500
∴ Volume of the entire triangular part = 12.5 500
∴ Volume of the entire triangular part = 6,250 ............................................. (Equation ii)
∴ Volume of the entire wall = Volume of the rectangular part + Volume of the triangular part
∴ Volume of the entire wall = 15,000 + 6,250
∴ Volume of the entire wall = 21,250 .

∴ Volume of the concrete in the wall is 21,250 .