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The depth of at which the value of acceleration due to gravity becomes 1/n the time the value of at the surface is (R= radius of earth)

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  1. R to the power of open parentheses k minus 18 x close parentheses end exponent
  2. R(fraction numerator n over denominator n plus 1 end fraction)
  3. R/n
  4. R/n2

    Answer:The correct answer is: R to the power of open parentheses k minus 18 x close parentheses end exponent

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