Maths-
General
Easy

Question

The derivative of e to the power of x cubed end exponent with respect to log  is

  1. e to the power of x cubed end exponent
  2. 3 x squared 2 e to the power of x cubed end exponent
  3. 3 x cubed e to the power of x cubed end exponent
  4. 3 x squared e to the power of x cubed end exponent plus 3 x squared

The correct answer is: 3 x cubed e to the power of x cubed end exponent


    Let y equals e to the power of x cubed end exponent comma z equals log invisible function application x
    On differentiating w.r.t. straight X, we get
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell fraction numerator d y over denominator d x end fraction equals e to the power of x cubed end exponent open parentheses 3 x squared close parentheses equals 3 x squared e to the power of x cubed end exponent text  and  end text fraction numerator d z over denominator d x end fraction equals 1 over x end cell row cell therefore fraction numerator d y over denominator d z end fraction equals fraction numerator fraction numerator d y over denominator d x end fraction over denominator fraction numerator d z over denominator d x end fraction end fraction equals fraction numerator 3 x squared e to the power of x cubed end exponent over denominator open parentheses 1 over x close parentheses end fraction equals 3 x cubed e to the power of x cubed end exponent end cell end table

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