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Question

The difference between two parallel sides of a trapezium is 8cm. The perpendicular distance between them is 19cm  while the area of trapezium is 760 sq.cm. What will be the lengths of the parallel sides.

hintHint:

Given , the difference between parallel sides ; we find the sum of lengths of
the parallel side from the area of trapezium formula by substituting the given values.
Now ,equate both the equations to get the values of lengths of parallel sides.

The correct answer is: 30.5 and 49.5


    Ans :- 30.5 cm ; 49.5 cm
    Explanation :-
    Let the length of parallel side be x and y where (x<y)
    Step 1:- frame the equation based on given conditions
    Difference between parallel side = y-x = 8 —- Eq1
    Given area of trapezium = 760 sq.cm
    Perpendicular distance or height = 19 cm .
    text  Area of trapezium  end text equals 1 half left parenthesis text  height  end text right parenthesis left parenthesis text  sum of lengths of parallel sides  end text right parenthesisnot stretchy rightwards double arrow 760 equals 1 half left parenthesis 19 right parenthesis text  (sum of lengths of parallel sides)  end text
    not stretchy rightwards double arrow text  sum of lengths of parallel sides  end text equals x plus y equals 40 cross times 2 equals 80 cm —- Eq2
    Step 2:- eliminate x to find y
    Adding Eq1 + Eq2 to eliminate x
    y minus x plus x plus y equals 19 plus 80 not stretchy rightwards double arrow 2 y equals 99 not stretchy rightwards double arrow y equals 49.5 cm
    Step 3:- Find x by substituting the value of y in Eq 2 .
    x plus y equals 80 cm not stretchy rightwards double arrow x plus 49.5 equals 80 not stretchy rightwards double arrow x equals 30.5 cm
    Therefore, 30.5 cm and 49.5 cm are the lengths of the parallel sides of trapezium.

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