Maths-
General
Easy

Question

The domain of f left parenthesis x right parenthesis equals fraction numerator 1 over denominator vertical line sin invisible function application x vertical line plus sin invisible function application x end fraction text  is  end text

  1. R
  2. U with n element of Z below left parenthesis left parenthesis 2 n plus 1 right parenthesis pi comma 2 left parenthesis n plus 1 right parenthesis pi right parenthesis
  3. U with n element of Z below left parenthesis 2 n pi comma left parenthesis 2 n plus 1 right parenthesis pi right parenthesis
  4. ϕ

hintHint:

in this question, we have to find the domain of f(x). For this denominator must not be equal to 0. Later with the help of range we will get for the sin x will be used to find the domain for f(x).

The correct answer is: U with n element of Z below left parenthesis 2 n pi comma left parenthesis 2 n plus 1 right parenthesis pi right parenthesis


    f left parenthesis x right parenthesis equals fraction numerator 1 over denominator open vertical bar sin space x close vertical bar plus sin space x end fraction
D e n o m i n a t o r not equal to 0
I f space sin space x space greater than 0 comma space space f left parenthesis x right parenthesis space i s space p o s i t i v e.
S o comma space sin space x space plus s i n space x space greater than 0
space space space space space space space space space space space space 2 sin space x space space space space space space space space greater than 0
space space space space space space space space space space space space s i n space x space space space space space space space space space space greater than 0
A s space sin x space greater than space 0 space
S o comma space 2 n straight pi less than straight x less than left parenthesis 2 straight n plus 1 right parenthesis straight pi
So comma space the space d o m a i n space is space U with n element of Z below left parenthesis 2 n pi comma left parenthesis 2 n plus 1 right parenthesis pi right parenthesis.

    Related Questions to study

    General
    Physics

    A particle is thrown in upward direction with initial velocity V0 It crosses point P at height  h at time t1 and t2 so t1 t2 ……..

    A particle is thrown in upward direction with initial velocity V0 It crosses point P at height  h at time t1 and t2 so t1 t2 ……..

    PhysicsGeneral
    General
    Maths-

    2.1 squared plus 3.2 squared plus 4.3 squared plus midline horizontal ellipsis horizontal ellipsis plus left parenthesis n plus 1 right parenthesis n squared equals

    2.1 squared plus 3.2 squared plus 4.3 squared plus midline horizontal ellipsis horizontal ellipsis plus left parenthesis n plus 1 right parenthesis n squared equals

    Maths-General
    General
    Maths-

    The domain of the function  f left parenthesis x right parenthesis equals fraction numerator tan invisible function application 2 x over denominator 6 cos invisible function application x plus 2 sin invisible function application 2 x end fraction text  is  end text

    The domain of the function  f left parenthesis x right parenthesis equals fraction numerator tan invisible function application 2 x over denominator 6 cos invisible function application x plus 2 sin invisible function application 2 x end fraction text  is  end text

    Maths-General
    parallel
    General
    Maths-

    Let f colon open square brackets 1 half comma 1 close square brackets not stretchy rightwards arrow left square bracket negative 1 comma 1 right square bracket is given byf left parenthesis x right parenthesis equals 4 x cubed minus 3 x text  then  end text f to the power of negative 1 end exponent left parenthesis x right parenthesis text  is given by  end text

    Let f colon open square brackets 1 half comma 1 close square brackets not stretchy rightwards arrow left square bracket negative 1 comma 1 right square bracket is given byf left parenthesis x right parenthesis equals 4 x cubed minus 3 x text  then  end text f to the power of negative 1 end exponent left parenthesis x right parenthesis text  is given by  end text

    Maths-General
    General
    Maths-

    If f left parenthesis x right parenthesis equals fraction numerator 10 to the power of x minus 10 to the power of negative x end exponent over denominator 10 to the power of x plus 10 to the power of negative x end exponent end fraction text  then  end text f to the power of negative 1 end exponent left parenthesis x right parenthesis equals

    If f left parenthesis x right parenthesis equals fraction numerator 10 to the power of x minus 10 to the power of negative x end exponent over denominator 10 to the power of x plus 10 to the power of negative x end exponent end fraction text  then  end text f to the power of negative 1 end exponent left parenthesis x right parenthesis equals

    Maths-General
    General
    Maths-

    If f left parenthesis x right parenthesis equals fraction numerator e to the power of x plus e to the power of negative x end exponent over denominator 2 end fraction ,then the inverse function of f left parenthesis x right parenthesis text  is  end text

    If f left parenthesis x right parenthesis equals fraction numerator e to the power of x plus e to the power of negative x end exponent over denominator 2 end fraction ,then the inverse function of f left parenthesis x right parenthesis text  is  end text

    Maths-General
    parallel
    General
    maths-

    If f left parenthesis x right parenthesis equals x squared plus x comma x equals 10 comma delta x equals 0.1 observe the following
    text  l)  end text delta f equals 2.11
    text  II)  end text d f equals 2.1
    text  III) Relative error in  end text x text  is  end text 1
    The true statements are

    If f left parenthesis x right parenthesis equals x squared plus x comma x equals 10 comma delta x equals 0.1 observe the following
    text  l)  end text delta f equals 2.11
    text  II)  end text d f equals 2.1
    text  III) Relative error in  end text x text  is  end text 1
    The true statements are

    maths-General
    General
    Maths-

    Statement I :f colon A not stretchy rightwards arrow B text  is one - one and  end text g colon B not stretchy rightwards arrow C text  is a one-one function, then gof  end text colon A not stretchy rightwards arrow C is one - one
    Statement II :text  If  end text f colon A not stretchy rightwards arrow B comma g colon B not stretchy rightwards arrow A are two functions such that g o f equals I subscript A text  and  end text fog equals I subscript B comma text  then  end text f equalsg to the power of negative 1 end exponent
    Staatement III : f left parenthesis x right parenthesis equals sec squared invisible function application x minus tan squared invisible function application x g left parenthesis x right parenthesis equals cosec squared invisible function application x minus cot squared invisible function application x comma text  then  end text f equals g

    Which of the above statement/s is/are true.

    Statement I :f colon A not stretchy rightwards arrow B text  is one - one and  end text g colon B not stretchy rightwards arrow C text  is a one-one function, then gof  end text colon A not stretchy rightwards arrow C is one - one
    Statement II :text  If  end text f colon A not stretchy rightwards arrow B comma g colon B not stretchy rightwards arrow A are two functions such that g o f equals I subscript A text  and  end text fog equals I subscript B comma text  then  end text f equalsg to the power of negative 1 end exponent
    Staatement III : f left parenthesis x right parenthesis equals sec squared invisible function application x minus tan squared invisible function application x g left parenthesis x right parenthesis equals cosec squared invisible function application x minus cot squared invisible function application x comma text  then  end text f equals g

    Which of the above statement/s is/are true.

    Maths-General
    General
    physics-

    A glass capillary sealed at the upper end is of length 0.11 m and internal diameter 2 cross times 1 0 to the power of negative 5 end exponentm. The tube is immersed vertically into a liquid of surface tension 5.06 cross times 1 0 to the power of negative 2 end exponent N/m. To what length has the capillary to be immersed so that the liquid level inside and outside the capillary becomes the same?

    A glass capillary sealed at the upper end is of length 0.11 m and internal diameter 2 cross times 1 0 to the power of negative 5 end exponentm. The tube is immersed vertically into a liquid of surface tension 5.06 cross times 1 0 to the power of negative 2 end exponent N/m. To what length has the capillary to be immersed so that the liquid level inside and outside the capillary becomes the same?

    physics-General
    parallel
    General
    physics-

    Water flows through a frictionless duct with a cross-section varying as shown in fig. . Pressure p at points along the axis is represented by: A resume water to be non-viscour

    Water flows through a frictionless duct with a cross-section varying as shown in fig. . Pressure p at points along the axis is represented by: A resume water to be non-viscour

    physics-General
    General
    physics-

    A cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4 cm below the interface. The density of oil is 0.6 g c m to the power of negative 3 end exponent. The mass of block is

    A cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4 cm below the interface. The density of oil is 0.6 g c m to the power of negative 3 end exponent. The mass of block is

    physics-General
    General
    physics-

    Water flows through a frictionless duct with a cross-section varying as shown in fig. Pressure p at points along the axis is represented by

    Water flows through a frictionless duct with a cross-section varying as shown in fig. Pressure p at points along the axis is represented by

    physics-General
    parallel
    General
    physics-

    The diagram shows a cup of tea seen from above. The tea has been stirred and is now rotating without turbulence. A graph showing the speed v with which the liquid is crossing points at a distance X from O along a radius XO would look like

    The diagram shows a cup of tea seen from above. The tea has been stirred and is now rotating without turbulence. A graph showing the speed v with which the liquid is crossing points at a distance X from O along a radius XO would look like

    physics-General
    General
    maths-

    f colon R to the power of plus not stretchy rightwards arrow R text  defined by  end text f left parenthesis x right parenthesis equals log subscript e invisible function application x comma x element of left parenthesis 0 comma 1 right parenthesis comma f left parenthesis x right parenthesis equals 2 log subscript e invisible function application x comma x element of left square bracket 1 comma straight infinity right parenthesis text  is  end text

    f colon R to the power of plus not stretchy rightwards arrow R text  defined by  end text f left parenthesis x right parenthesis equals log subscript e invisible function application x comma x element of left parenthesis 0 comma 1 right parenthesis comma f left parenthesis x right parenthesis equals 2 log subscript e invisible function application x comma x element of left square bracket 1 comma straight infinity right parenthesis text  is  end text

    maths-General
    General
    Maths-

    f colon R to the power of plus not stretchy rightwards arrow R text  defined by  end text f left parenthesis x right parenthesis equals 2 to the power of x comma x element of left parenthesis 0 comma 1 right parenthesis comma f left parenthesis x right parenthesis equals 3 to the power of x comma x element of left square bracket 1 comma straight infinity right parenthesis text  is  end text

    f colon R to the power of plus not stretchy rightwards arrow R text  defined by  end text f left parenthesis x right parenthesis equals 2 to the power of x comma x element of left parenthesis 0 comma 1 right parenthesis comma f left parenthesis x right parenthesis equals 3 to the power of x comma x element of left square bracket 1 comma straight infinity right parenthesis text  is  end text

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.