Chemistry-
General
Easy

Question

The enzyme pepsin hydrolyses:

  1. Proteins to amino acids
  2. Fats to fatty acids
  3. Glucose to ethyl alcohol
  4. Polysaccharides to monosaccharides

The correct answer is: Proteins to amino acids

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The magnetic induction at the point O, if the wire carrying current I is

   

The magnetic induction at the point O, if the wire carrying current I is

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Let f : R →R and g : R →R be continuous functions, then the value of not stretchy integral subscript negative pi divided by 2 end subscript superscript pi text /2 end text end superscript blank (f(x) + f(-x)) (g(x) – g(-x)) dx, is equal to

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A wire is bent in the form of a circular arc with a straight portion AB If the current in the wire is i, then the magnetic induction at O is

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The figure shows a unifrom conducting structure which carries current i with each small square has side a The structure is kept in a uniform magnetic field B Then the magnetic force on the structure will be

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Two long parallel conductors carry currents i subscript 1 end subscript equals 3 A text  and  end text i subscript 2 end subscript equals 3 A both are directed into the plane of paper The magnitude of resultant magnetic field at point ‘P; is

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What amount of bromine will be required to convert 2 g of phenol into 2, 4, 6-tribromo phenol?

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A wire bent in the form a right angled triangle PQR, carries a current 1 A It is placed in a region of a uniform magnetic field B= 0.2T If PR = 1m, the net force on the wire is

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A current i A = 2 be flowing in each part of a wire frame as shown in fig The frame is a combination of two equilateral triangles ACD and CDE of side 1m It is placed in uniform magnetic field B=4T acting perpendicular to the plane of frame The magnitude of magnetic force acting on the frame is

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Wires 1 and 2 carrying currents i1 and i2 respectively are inclined at an angle q to each other What is the force on a small element dl of wire 2 at a distance of r from wire 1 (as shown in figure) due to the magnetic field of wire 1

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PQ is a uniform rod of length l and mass m carrying current i and is suspended in uniform magnetic field of induction B ur acting inward as shown in figure The tension in each string is

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Two wires AO and OC carry currents i as shown in figure One end of both the wires extends to infinity angle A O C equals alpha, the magnitude of magnetic field at a point P on the bisector of the two wires at a distance r from O is

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Two identical discs of same radius R are rotating about their axes in opposite directions with the same constant angular speed omega. The discs are in the same horizontal plane. At time t equals 0, the points P and Q are facing each other as shown in figure. The relative speed between the two points P and Q is V subscript r end subscript as function of times best represented by


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So two half cycles will take place

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So, V subscript r end subscript equals 2 omega R sin invisible function application left parenthesis omega t right parenthesis
At t equals T divided by 2 comma blank V subscript r end subscript equals 0
So two half cycles will take place
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Consider the given velocity-time graph It represents the motion of

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