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General

General

Easy

Question

The graph of $y equals 2 x squared plus 10 x plus 12$ is shown. If the graph crosses the y -axis at the point (o, k) , what is the value of k?

2
6
10
12

hint Hint:

Hint:

An equation that can be written in the form of $a x squared plus b x plus c$ is quadratic, where $a not equal to 0$ .

The correct answer is: 12

Explanation:

We have given a quadratic equation $y equals 2 x squared plus 10 x plus 12$ .

We have to find the point, where the graph of the given function cut the y-axis .

We will put x=0 and then find the value of y.

Step 1 of 1:

We have given a function $y equals 2 x squared plus 10 x plus 12$ .
Now, when the graph of the function cut y-axis, then the value of x=0.
So,
Put the value x=0 in the given function

$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals 2 x squared plus 10 x plus 12 end cell row cell y equals 2 left parenthesis 0 right parenthesis squared plus 10 left parenthesis 0 right parenthesis plus 12 end cell row cell y equals 12 end cell end table$

So, The point at which the given function cuts the y-axis is (0,12).

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