Question
The inner diameter of a cylindrical wooden pipe is 24 cm, and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cubic cm of wood has a mass of 0.6 gm.
The correct answer is: The mass of the pipe is 3432 gm.
The wooden pipe is hollow inside. So, we have to calculate its width volume, by subtracting the volume with inner radius from the volume with outer radius. Then, we multiply the given mass for 1 cubic cm of wood with the calculated area to get the total mass of the pipe.
We take = 
22/7.
Step 1 of 3:
The inner diameter of a cylindrical wooden pipe is 24 cm. So, the inner radius is 
12 cm.
The outer diameter of a cylindrical wooden pipe is 24 cm. So, the outer radius is 
14 cm.
Step 2 of 3:
We know that, if the radius of a cylinder is r and height be h, then the volume is 
.
Now, the volume of the wood only is 
Step 3 of 3:
It is given that 1 cubic cm of wood has a mass of 0.6 gm.
5720 cm3 of wood would have a mass of 
gm
Final Answer:
The mass of the pipe is 3432 gm.
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A simpler way of solving this question is to check where the decrease in the graph has the steepest slope between two months. It is clearly between the months June and July. Here, it is obvious; but that may not be the case in other problems. So, we need to always calculate the actual decrease in the value.
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Note:
A line of best fit is also called a trendline. The equation of a line of best fit can be represented as y = m x + b , where m is the slope and b is the y-intercept. This is the equation of a line. It is a line that minimizes the distance of the actual homeruns from the predicted homeruns.
