Maths-
General
Easy

Question

The length of the tangent of the curves x equals a cos cubed invisible function application theta comma y equals a sin cubed invisible function application theta left parenthesis a greater than 0 right parenthesis is

  1. a sin squared invisible function application theta
  2. a sin squared invisible function application theta vertical line tan invisible function application theta vertical line
  3. a sin squared invisible function application theta vertical line cos invisible function application theta vertical line
  4. a sin to the power of 4 invisible function application theta vertical line sec invisible function application theta vertical line

hintHint:

We have to find the length of the tangent. We are given the values of x and y as function of theta. We will use the formula of length of tangent to find the value.

The correct answer is: a sin squared invisible function application theta


    The given values of x and y are as follows:
    x = acos3θ
    y = asin3theta
    The formula for length of tangent is
    Length = open vertical bar y square root of 1 plus open parentheses fraction numerator d x over denominator d y end fraction close parentheses squared end root close vertical bar
    We will first differentiate x and y w.r.t θ and then find fraction numerator d x over denominator d y end fraction
    Differentiating x w.r.t θ
    x space equals space a cos cubed theta
fraction numerator d x over denominator d theta end fraction equals a left parenthesis 3 cos squared theta right parenthesis fraction numerator d over denominator d theta end fraction cos theta
space space space space space space space equals 3 a cos squared theta left parenthesis negative sin theta right parenthesis
space space space space space space space equals negative 3 a cos squared theta sin theta
space space space space space space
    Differentiating y w.r.t θ
    fraction numerator d y over denominator d theta end fraction equals a open parentheses 3 sin squared theta close parentheses fraction numerator d over denominator d theta end fraction left parenthesis sin theta right parenthesis
space space space space space space space equals 3 a sin squared theta cos theta
    Now,
    fraction numerator d x over denominator d y end fraction equals fraction numerator d x over denominator d theta end fraction plus fraction numerator d theta over denominator d y end fraction
space space space space space space space equals negative 3 a cos squared theta sin theta space cross times space fraction numerator 1 over denominator 3 a sin squared theta cos theta end fraction
space space space space space space space equals negative 1 fraction numerator cos theta over denominator sin theta end fraction
space space space space space space space space equals negative fraction numerator 1 over denominator tan theta end fraction
    We will substitute this value in the formula of length of tangent.
    L e n g t h space equals space open vertical bar y square root of 1 space plus space open parentheses fraction numerator d x over denominator d y end fraction close parentheses squared end root close vertical bar
space space space space space space space space space space space space space space equals open vertical bar a sin cubed theta square root of 1 space plus space open parentheses fraction numerator negative 1 over denominator tan theta end fraction close parentheses squared end root close vertical bar
space space space space space space space space space space space space space space equals open vertical bar a sin cubed theta square root of 1 space plus space fraction numerator 1 over denominator tan squared theta end fraction end root close vertical bar
space space space space space space space space space space space space space space equals open vertical bar a sin cubed theta fraction numerator square root of tan squared theta space plus space 1 end root over denominator square root of tan squared theta end root end fraction close vertical bar
space space space space space space space space space space space space space space equals open vertical bar fraction numerator a sin cubed theta s e c theta over denominator tan theta end fraction close vertical bar space space space space space space space space space space space space space space space space space... left parenthesis 1 space plus space tan squared A space equals space s e c squared A right parenthesis
space space space space space space space space space space space space space equals open vertical bar fraction numerator begin display style fraction numerator a sin cubed theta over denominator cos theta end fraction end style over denominator begin display style fraction numerator sin theta over denominator cos theta end fraction end style end fraction close vertical bar space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis s e c A space equals space 1 divided by cos A right parenthesis
space space space space space space space space space space space space space equals a sin squared theta
space space space

space space space space space space space space space space space
    So, length of the tangent is asin2θ

    For such questions, we should know the properties of trignometric functions and their different formulas.

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