Question

# The parallel sides of an isosceles trapezium are 16cm and 28cm and equal sides are 24cm each. Find the area ?

Hint:

### Draw the parallel line from B parallel to AD which cuts the CD at E .

We get a triangle and parallelogram. we find the area of triangle in both heron's

method and using formula area = ½ b × h and equating we get height h

Now , find the area of Trapezium = ½ height × (sum of lengths of parallel sides).

## The correct answer is: 132√15 (or) 511.2338 cm2.

### Ans :- .

Explanation :-

Step 1:- Given lengths of parallel sides is 16 and 28 cm .

Length of non parallel sides is 24 and 24 cm

We get a triangle and parallelogram ABED

we get BE = 24 cm ; DE = 16 cm (opposites sides of parallelogram )

CE = CD-DE = 28 - 16 = 12 cm .

Step 2:- Equate the areas and find value of height h

Step 3:-Find the area of trapezium

Therefore, Area of trapezium ABCD =

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