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Chemistry-

General

Easy

Question

The reaction given below is called: $C subscript 2 H subscript 5 O H plus S O C l subscript 2 ⟶ C subscript 2 H subscript 5 C l plus S O subscript 2 plus H C l$

Kharasch effect
Wurtz reaction
Darzen’s reaction
Hunsdicker reaction

The correct answer is: Darzen’s reaction

It is name reaction.

Related Questions to study

$I s o$ - butyl alcohol A True statement about is

I s o

- butyl alcohol is secondary alcohol

$I s o$ - butyl alcohol A True statement about is

chemistry-General

I s o

- butyl alcohol is secondary alcohol

General formula of primary alcohol is:

General formula of primary alcohol is:

chemistry-General

If $A equals d i g left parenthesis 2 comma negative 1 , 3 right parenthesis comma B equals d i g left parenthesis negative 1 , 3 comma 2 right parenthesis$ , then $A to the power of 2 end exponent B equals$

A to the power of 2 end exponent B equals left parenthesis A. A right parenthesis B equals open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets. open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets

equals open square brackets table row 4 0 0 row 0 1 0 row 0 0 9 end table close square brackets open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets equals open square brackets table row cell negative 4 end cell 0 0 row 0 3 0 row 0 0 18 end table close square brackets

If $A equals d i g left parenthesis 2 comma negative 1 , 3 right parenthesis comma B equals d i g left parenthesis negative 1 , 3 comma 2 right parenthesis$ , then $A to the power of 2 end exponent B equals$

A to the power of 2 end exponent B equals left parenthesis A. A right parenthesis B equals open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets. open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets

equals open square brackets table row 4 0 0 row 0 1 0 row 0 0 9 end table close square brackets open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets equals open square brackets table row cell negative 4 end cell 0 0 row 0 3 0 row 0 0 18 end table close square brackets

parallel

Diethyl ether is soluble in:

Soluble in strong acids ethers are Lewis base.

Diethyl ether is soluble in:

chemistry-General

Soluble in strong acids ethers are Lewis base.

Glycerol reacts with potassium bisulphate to produce

Glycerol is dehydrated on heating with

K H S O subscript 4

Glycerol reacts with potassium bisulphate to produce

chemistry-General

Glycerol is dehydrated on heating with

K H S O subscript 4

If [m n] $open square brackets table row m row n end table close square brackets equals left square bracket 25 right square bracket$ and m< n, then (m, n) =

It is obvious that (m,n) =(3, 4).

If [m n] $open square brackets table row m row n end table close square brackets equals left square bracket 25 right square bracket$ and m< n, then (m, n) =

It is obvious that (m,n) =(3, 4).

parallel

Power alcohol is a mixture of petrol and alcohol in the ratio:

Power alcohol is used to generate power.

Power alcohol is a mixture of petrol and alcohol in the ratio:

chemistry-General

Power alcohol is used to generate power.

The compound that will react most readily with $N a O H$ to form methanol is:

open parentheses C H subscript 3 close parentheses subscript 4 N to the power of plus I to the power of minus not stretchy ⟶ with N a O H on top open parentheses C H subscript 3 close parentheses subscript 4 N to the power of plus O H to the power of minus not stretchy rightwards arrow with straight capital delta on top open parentheses C H subscript 3 close parentheses subscript 3 N plus C H subscript 3 O H

The reaction is more spontaneous for a better leaving group,

I to the power of minus

Also, methyl group with

plus N

plus v e space

charge on N-atom to release

I to the power of minus

The compound that will react most readily with $N a O H$ to form methanol is:

chemistry-General

open parentheses C H subscript 3 close parentheses subscript 4 N to the power of plus I to the power of minus not stretchy ⟶ with N a O H on top open parentheses C H subscript 3 close parentheses subscript 4 N to the power of plus O H to the power of minus not stretchy rightwards arrow with straight capital delta on top open parentheses C H subscript 3 close parentheses subscript 3 N plus C H subscript 3 O H

The reaction is more spontaneous for a better leaving group,

I to the power of minus

Also, methyl group with

plus N

plus v e space

charge on N-atom to release

I to the power of minus

The system of equations $alpha x plus y plus z equals alpha minus 1 x plus alpha y plus z equals alpha minus 1 x plus y plus alpha z equals alpha minus 1$ has no solution, if $alpha$ is

For no solution or infinitely many solutions

open vertical bar table row alpha 1 1 row 1 alpha 1 row 1 1 alpha end table close vertical bar equals 0 rightwards double arrow alpha equals 1 comma alpha equals negative 2

alpha equals 1

, clearly there are infinitely many solutions and when we put

alpha equals negative 2

in given system of equations and adding them together L.H.S

not equal to

R.H.S. i.e., No solution.

The system of equations $alpha x plus y plus z equals alpha minus 1 x plus alpha y plus z equals alpha minus 1 x plus y plus alpha z equals alpha minus 1$ has no solution, if $alpha$ is

For no solution or infinitely many solutions

open vertical bar table row alpha 1 1 row 1 alpha 1 row 1 1 alpha end table close vertical bar equals 0 rightwards double arrow alpha equals 1 comma alpha equals negative 2

alpha equals 1

, clearly there are infinitely many solutions and when we put

alpha equals negative 2

in given system of equations and adding them together L.H.S

not equal to

R.H.S. i.e., No solution.

parallel

Dialkylsulphides are known as:

R long dash S long dash R space o r space R long dash S R apostrophe space

are thioethers.

Dialkylsulphides are known as:

chemistry-General

R long dash S long dash R space o r space R long dash S R apostrophe space

are thioethers.

How many isomers of $C subscript 5 H subscript 1 1 O H$ will be primary alcohols?

How many isomers of $C subscript 5 H subscript 1 1 O H$ will be primary alcohols?

chemistry-General

The formula for allyl alcohol is:

long dash O H g p. i s space o n space a l l y l space g p. space left parenthesis C H subscript 2 equals C H long dash C H subscript 2 long dash right parenthesis

The formula for allyl alcohol is:

chemistry-General

long dash O H g p. i s space o n space a l l y l space g p. space left parenthesis C H subscript 2 equals C H long dash C H subscript 2 long dash right parenthesis

parallel

Alcohols may behave as:

Alcohols are neutral as they do not influence the pH. Due to — bond, they possess Bronsted acid nature showing cleavage of — bond. Also due to the presence of lone pair of electron on oxygen atom, they act as Lewis base. The reactivity order is based on of alkyl groups.
Lewis base order :

3 space ͦ greater than 2 space ͦ greater than 1 space ͦ

Bronsted acid order :

1 space ͦ greater than 2 space ͦ greater than 3 space ͦ

Alcohols may behave as:

chemistry-General

Alcohols are neutral as they do not influence the pH. Due to — bond, they possess Bronsted acid nature showing cleavage of — bond. Also due to the presence of lone pair of electron on oxygen atom, they act as Lewis base. The reactivity order is based on of alkyl groups.
Lewis base order :

3 space ͦ greater than 2 space ͦ greater than 1 space ͦ

Bronsted acid order :

1 space ͦ greater than 2 space ͦ greater than 3 space ͦ

$Lt subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator x left parenthesis 1 plus a cos space x right parenthesis minus b sin space x over denominator x cubed end fraction equals 1$ then a=, b=

$Lt subscript x not stretchy rightwards arrow 0 end subscript space fraction numerator x left parenthesis 1 plus a cos space x right parenthesis minus b sin space x over denominator x cubed end fraction equals 1$ then a=, b=

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x 10 to the power of x minus x over denominator 1 minus cos space x end fraction equals$

$L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator x 10 to the power of x minus x over denominator 1 minus cos space x end fraction equals$

parallel

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