Maths-
General
Easy

Question

The sum of all the numbers formed by taking all the digits from 2,3,4,5 is:

  1. 6660000
  2. 93325
  3. 93324
  4. 10368000

Hint:

To find the sum of all the numbers formed with 2, 3, 4 and 5, it is necessary to know in how many numbers each of 2, 3, 4, 5 will be in the unit place. Then we can find the sum of all the numbers in the unit place similarly we will find the sum of all the numbers in tens, hundreds and thousands place. At last we will find the required sum.

The correct answer is: 93324


    The number of numbers having 2 in the unit place= 3! =6
    The number of numbers having 3 in the unit place= 3! =6
    The number of numbers having 4 in the unit place= 3! =6
    The number of numbers having 5 in the unit place= 3! =6
    So the sum of the digits in the unit place of all the numbers=2 cross times 6 plus 3 cross times 6 plus 4 cross times 6 plus 5 cross times 6
    =12+18+24+30
    =84
    Similarly the sum of the digits of all the numbers in each of the other places=84
    The required sum =84 cross times 1000 plus 84 cross times 100 plus 84 cross times 10 plus 84
    =84(1000+100+10+1)
    =84cross times 1111
    =93324

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