The sum of the series, sin theta sec 3theta+sin 3theta sec 3^-Turito

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The sum of the series, $sin space theta sec space 3 theta plus sin space 3 theta sec space 3 squared theta plus sin space 3 squared theta sec space 3 cubed theta plus times times$ upto n terms, is

Maths-General

$\frac{1}{2} [\tan 3^{n} θ - \tan 3^{x - 1} θ]$
$[\tan 3^{n} θ - \tan θ]$
$\frac{1}{2} [\tan 3^{n} θ - \tan θ]$
$\frac{1}{2} (\tan 3^{n} θ - 1)$

Answer:The correct answer is: $1 half open square brackets tan space 3 to the power of n theta minus tan space theta close square brackets$

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A long cylindrical tube carries a highly polished piston and has a side opening. A tuning fork of frequency n is sounded at the sound heard by the listener charges if the piston is moves in or out. At a particular position of the piston is moved through a distance of 9 cm, the intensity of sound becomes minimum, if the speed of sound is 360 m/s, the value of n is

When piston moves a distance

x subscript 1 end subscript

, path difference change by 2 xs.

therefore

the path difference between maxima and consecutive minima=

lambda divided by 2

∴

2 x equals lambda divided by 2

Or
λ=4x=4×9 cm=36cm=0.36m

n equals fraction numerator v over denominator lambda end fraction equals fraction numerator 360 over denominator 0.36 end fraction equals 1000 blank H z

A long cylindrical tube carries a highly polished piston and has a side opening. A tuning fork of frequency n is sounded at the sound heard by the listener charges if the piston is moves in or out. At a particular position of the piston is moved through a distance of 9 cm, the intensity of sound becomes minimum, if the speed of sound is 360 m/s, the value of n is

physics-General

When piston moves a distance

x subscript 1 end subscript

, path difference change by 2 xs.

therefore

the path difference between maxima and consecutive minima=

lambda divided by 2

∴

2 x equals lambda divided by 2

Or
λ=4x=4×9 cm=36cm=0.36m

n equals fraction numerator v over denominator lambda end fraction equals fraction numerator 360 over denominator 0.36 end fraction equals 1000 blank H z

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The value of $cot space fraction numerator 7 pi over denominator 16 end fraction plus 2 cot space fraction numerator 3 pi over denominator 8 end fraction plus cot space fraction numerator 15 pi over denominator 16 end fraction$ is

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The sum of the series, $sin space theta sec space 3 theta plus sin space 3 theta sec space 3 squared theta plus sin space 3 squared theta sec space 3 cubed theta plus times times$ upto n terms, is

$\frac{1}{2} [\tan 3^{n} θ - \tan 3^{x - 1} θ]$
$[\tan 3^{n} θ - \tan θ]$
$\frac{1}{2} [\tan 3^{n} θ - \tan θ]$
$\frac{1}{2} (\tan 3^{n} θ - 1)$

Answer:The correct answer is: $1 half open square brackets tan space 3 to the power of n theta minus tan space theta close square brackets$

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The sum of the series, upto n terms, is

Answer:The correct answer is:

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The sum of the series, $sin space theta sec space 3 theta plus sin space 3 theta sec space 3 squared theta plus sin space 3 squared theta sec space 3 cubed theta plus times times$ upto n terms, is

Answer:The correct answer is: $1 half open square brackets tan space 3 to the power of n theta minus tan space theta close square brackets$

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