Maths-
General
Easy

Question

To get from point A to point B you must avoid walking through a pond. To avoid the pond, you must walk 34 meters south and 41 meters east. To the nearest meter, how many meters would be saved if it were possible to walk through the pond?

hintHint:

Pythagoras' theorem states that “In a right-angled triangle,  the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
If a is the perpendicular, b is the base, and c is the hypotenuse, then according to the definition, the Pythagoras Theorem formula is given as
c2= a2 + b2
 

The correct answer is: the meters saved if it were possible to walk through the pond is 19.74 m.


    In the given question,
    Length of perpendicular(a) = 34 m
    Length of base(b) = 41 m
    Let’s say that the length of the shortest path is given as d and here the shortest path is the hypotenuse of the right-angled triangle.
    Using Pythagoras theorem

    d2 = a2 + b2

    d2 = 342 + 412

    d2 = 2837

    d = square root of 2837 = 53.26 m
    Distance travelled to reach point B from A = 34 + 41 = 75 m
    The meters saved if it were possible to walk through the pond = 75 - 53.26 = 19.74 m
    Final Answer:
    Hence, the meters saved if it were possible to walk through the pond is 19.74 m.

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