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General
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Question

L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of x minus sin invisible function application x minus 1 over denominator x end fraction

  1. 1
  2. e to the power of x
  3. X
  4. 0

hintHint:

In this question we will first use the L hospital theorem. Then we will put value of x.

The correct answer is: 0


    L t subscript x not stretchy rightwards arrow 0 end subscript fraction numerator e to the power of x minus sin invisible function application x minus 1 over denominator x end fraction
    using L hospital theorem,
    limit as x rightwards arrow 0 of fraction numerator begin display style fraction numerator d e to the power of x over denominator d x end fraction end style minus begin display style fraction numerator d sin x space minus 1 over denominator d x end fraction end style over denominator begin display style fraction numerator d x over denominator d x end fraction end style end fraction
equals limit as x rightwards arrow 0 of fraction numerator e to the power of x minus cos space x over denominator 1 end fraction
equals e to the power of 0 minus cos space 0
equals 1 minus 1 equals 0

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