Physics
General
Easy

Question

Two particle of equal mass go round a circle of radius r. Under the action of their mutual gravitational force. The speed of each particle is …….

  1. v=fraction numerator 1 over denominator 2 r end fraction square root of fraction numerator 1 over denominator G m end fraction end root
  2. v=square root of fraction numerator G m over denominator 2 r end fraction end root
  3. v=1 half square root of fraction numerator G m over denominator r end fraction end root
  4. v=square root of fraction numerator 4 G m over denominator r end fraction end root

The correct answer is: v=1 half square root of fraction numerator G m over denominator r end fraction end root

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