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Question

Use binomial theorem to expandleft parenthesis 2 c plus d right parenthesis to the power of 6

The correct answer is: The expansion of the expression can also be found using the Pascal’s triangle. But, it is necessary to remember the values of the triangle to write down the expansion.


    ANSWER:
    Hint:
    The binomial expansion is left parenthesis x plus y right parenthesis to the power of n equals sum from k equals 0 to n of   n C subscript k x to the power of n minus k end exponent y to the power of k , here n greater or equal than 0 .
    We are asked to use binomial theorem to expand left parenthesis 2 c plus d right parenthesis to the power of 6
    Step 1 of 2:
    The given expression is left parenthesis 2 c plus d right parenthesis to the power of 6 , where x equals 2 cstraight & y equals d .Here, the value of n=6, hence we would have 6+1=7 terms in the expression.
    Step 2 of 2:
    Substitute the values of  left parenthesis 2 c plus d right parenthesis to the power of 6in the binomial expression;
    left parenthesis 2 c plus d right parenthesis to the power of 6 equals 6 C subscript 0 left parenthesis 2 c right parenthesis to the power of 6 plus 6 C subscript 1 left parenthesis 2 c right parenthesis to the power of 5 left parenthesis d right parenthesis plus 6 C subscript 2 left parenthesis 2 c right parenthesis to the power of 4 left parenthesis d right parenthesis squared plus 6 C subscript 3 left parenthesis 2 c right parenthesis cubed left parenthesis d right parenthesis cubed plus 6 C subscript 4 left parenthesis 2 c right parenthesis squared left parenthesis d right parenthesis to the power of 4 plus 6 C subscript 5 left parenthesis 2 c right parenthesis left parenthesis d right parenthesis to the power of 5 plus 6 C subscript 6 left parenthesis d right parenthesis to the power of 6
    equals 64 c to the power of 6 plus 6 open parentheses 32 c to the power of 5 close parentheses left parenthesis d right parenthesis plus 15 open parentheses 16 c to the power of 4 close parentheses open parentheses d squared close parentheses plus 20 open parentheses 8 c cubed close parentheses open parentheses d cubed close parentheses plus 15 open parentheses 4 c squared close parentheses open parentheses d to the power of 4 close parentheses plus 6 left parenthesis 2 c right parenthesis open parentheses d cubed close parentheses plus d to the power of 6
    equals 64 c to the power of 6 plus 192 d c to the power of 5 plus 240 d squared c to the power of 4 plus 160 d cubed c cubed plus 60 d to the power of 4 c squared plus 12 d to the power of 5 c plus d to the power of 6
    Thus, the expansion is:left parenthesis 2 c plus d right parenthesis to the power of 6 equals 64 c to the power of 6 plus 192 d c to the power of 5 plus 240 d squared c to the power of 4 plus 160 d cubed c cubed plus 60 d to the power of 4 c squared plus 12 d to the power of 5 c plus d to the power of 6
    Note:
    The expansion of the expression can also be found using the Pascal’s triangle. But, it is necessary to remember the values of the triangle to write down the expansion.

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