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# Vtotal = Vcone 1+Vcone 2 Find the volume of the composite solid.

Use 3.14 for pi.

- 891.76 cm
^{3} - 420.76 cm
^{3} - 626.76 cm
^{3} - 765.67 cm
^{3}

^{3}^{3}^{3}^{3}Hint:

### Volume of a cone = ()πr2h

## The correct answer is: 891.76 cm^{3}

### We have given the dimensions of a Cones in the given figure

For Cone 1

Radius, r = 6 cm

Height, h = 7 cm

For Cone 2

Radius, R = 10 cm

Height, H = 6 cm

We have to find the volume of the given cone

We know that

Volume of a Cone 1 = ()πr^{2}h

= ()(3.14)(6 x 6)(7)

= ()(3.14) (36 x 7)

= ()(3.14)(252)

= 791.28 / 3

= 263.76 cm^{3}

Volume of a Cone 1 = ()πR^{2}H

= ()(3.14)(10 x 10)(6)

= ()(3.14) (100 x 6)

= ()(3.14)(600)

= 188

= 628 cm^{3}

We know that V_{total}=V_{cone 1}+V_{cone 2}

V_{total }= 263.76 + 628 = 891.76 cm^{3}

Therefore, the total volume of the composite solid is 891.76 cm^{3}

Therefore correct option is a)891.76 cm^{3} .

^{3}

^{2}H

^{3}

We know that V

_{total}=V

_{cone 1}+V

_{cone 2}

V

_{total }= 263.76 + 628 = 891.76 cm

^{3}

Therefore, the total volume of the composite solid is 891.76 cm

^{3}

Therefore correct option is a)891.76 cm

^{3}.

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