Maths-

General

Easy

### Question

#### what are the greatest common factors of 6 and 8:

- 1
- 8
- 2
- 6

#### The correct answer is: 2

#### Factors of 6: 1, 2, 3, 6

Factors of 8: 1,2, 4,8

Common factors are 1 and 2.

Greatest common factor: 2

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### Related Questions to study

Maths-

#### What is 25 percent of 1000

25 percent of 1000 = (25/ 100) x 1000 = 250

#### What is 25 percent of 1000

Maths-General

25 percent of 1000 = (25/ 100) x 1000 = 250

Maths-

#### Which of the following ratio is equivalent to 8:2

8 and 2 both are divisible by 2

(8/2)/(2/2)

4/1

4:1

(8/2)/(2/2)

4/1

4:1

#### Which of the following ratio is equivalent to 8:2

Maths-General

8 and 2 both are divisible by 2

(8/2)/(2/2)

4/1

4:1

(8/2)/(2/2)

4/1

4:1

Maths-

#### The surface area of a cuboid is 3600 sq m. If its dimensions are in the ratio 4:2:2, find its volume.

let the dimensions of the cuboid be 4x,2x,2x.

surface area of cuboid

=2[4x*2x + 2x*2x + 2x*4x]

=2[8x

=2[20x

=40x

According to the question,

40x

X

X

X=(9)

X=3

Dimensions =12m , 6m , 6m

Volume= 12*6*6

Volume= 432 cu m

surface area of cuboid

=2[4x*2x + 2x*2x + 2x*4x]

=2[8x

^{2 }+ 4x^{2}+ 8x^{2}]=2[20x

^{2}]=40x

^{2}According to the question,

40x

^{2}=3600X

^{2 }=3600/40X

^{2}=9X=(9)

^{1/2}X=3

Dimensions =12m , 6m , 6m

Volume= 12*6*6

Volume= 432 cu m

#### The surface area of a cuboid is 3600 sq m. If its dimensions are in the ratio 4:2:2, find its volume.

Maths-General

let the dimensions of the cuboid be 4x,2x,2x.

surface area of cuboid

=2[4x*2x + 2x*2x + 2x*4x]

=2[8x

=2[20x

=40x

According to the question,

40x

X

X

X=(9)

X=3

Dimensions =12m , 6m , 6m

Volume= 12*6*6

Volume= 432 cu m

surface area of cuboid

=2[4x*2x + 2x*2x + 2x*4x]

=2[8x

^{2 }+ 4x^{2}+ 8x^{2}]=2[20x

^{2}]=40x

^{2}According to the question,

40x

^{2}=3600X

^{2 }=3600/40X

^{2}=9X=(9)

^{1/2}X=3

Dimensions =12m , 6m , 6m

Volume= 12*6*6

Volume= 432 cu m

Maths-

#### which multiplication property states that,”The mode of grouping the factors does not change the result of the multiplication”.

associative property i.e.,

(a*b)*c =a*(b*c)

(a*b)*c =a*(b*c)

#### which multiplication property states that,”The mode of grouping the factors does not change the result of the multiplication”.

Maths-General

associative property i.e.,

(a*b)*c =a*(b*c)

(a*b)*c =a*(b*c)

Maths-

#### 4 divided by 16/11

4 ÷ 16/11 = 4 x 11/16 = 11/4

#### 4 divided by 16/11

Maths-General

4 ÷ 16/11 = 4 x 11/16 = 11/4

Maths-

#### Divide 56 by 3:

Q=18, R=2

#### Divide 56 by 3:

Maths-General

Q=18, R=2

Maths-

#### What is the mean of first five whole numbers

Mean = (0+1+2+3+4) / 5 = 2

#### What is the mean of first five whole numbers

Maths-General

Mean = (0+1+2+3+4) / 5 = 2

Maths-

#### what is the opposite integer of 4:

opposite integer of 4 is -4

#### what is the opposite integer of 4:

Maths-General

opposite integer of 4 is -4

Maths-

#### What is the place value of 3 in 234,569

Ten-thousands

#### What is the place value of 3 in 234,569

Maths-General

Ten-thousands

Maths-

#### In a school, there are 1000 students. Out of these, 700 students are girls. Find the percentage of boys and girls in the school.

Percentage of girls=(700/1000)*100

=70%

No. of boys= 1000-700=300

Percentage of boys= (300/1000)*100

=30%

=70%

No. of boys= 1000-700=300

Percentage of boys= (300/1000)*100

=30%

#### In a school, there are 1000 students. Out of these, 700 students are girls. Find the percentage of boys and girls in the school.

Maths-General

Percentage of girls=(700/1000)*100

=70%

No. of boys= 1000-700=300

Percentage of boys= (300/1000)*100

=30%

=70%

No. of boys= 1000-700=300

Percentage of boys= (300/1000)*100

=30%

Maths-

#### Find the least common multiple of 9 and 10.

LCM of 9 and 10 = 3*3*2*5= 90

#### Find the least common multiple of 9 and 10.

Maths-General

LCM of 9 and 10 = 3*3*2*5= 90

Maths-

#### There are two circle with same centre O. The radius of larger circle is 4cm and that of the smaller circle is 2cm.

Find area of the shaded region.

Ar of shaded region =ar. of larger circle – ar. of smaller circle

{ar. of circle = 22/7*r*r}

= 22/7*4*4-22/7*2*2

=22/7(16-4)

=22/7*12

=37.7 sq cm

{ar. of circle = 22/7*r*r}

= 22/7*4*4-22/7*2*2

=22/7(16-4)

=22/7*12

=37.7 sq cm

#### There are two circle with same centre O. The radius of larger circle is 4cm and that of the smaller circle is 2cm.

Find area of the shaded region.

Maths-General

Ar of shaded region =ar. of larger circle – ar. of smaller circle

{ar. of circle = 22/7*r*r}

= 22/7*4*4-22/7*2*2

=22/7(16-4)

=22/7*12

=37.7 sq cm

{ar. of circle = 22/7*r*r}

= 22/7*4*4-22/7*2*2

=22/7(16-4)

=22/7*12

=37.7 sq cm

Maths-

#### Write 5 in roman numbers

V

#### Write 5 in roman numbers

Maths-General

V

Maths-

#### Is 4/16 is equivalent to

Dividing the numerator and denominator by 4, we get 1/4

#### Is 4/16 is equivalent to

Maths-General

Dividing the numerator and denominator by 4, we get 1/4

Maths-

#### Which of the following is a roman number

V is 5 in roman numbers

#### Which of the following is a roman number

Maths-General

V is 5 in roman numbers