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Question

table attributes columnspacing 1em end attributes row cell left parenthesis x plus 2 right parenthesis squared plus left parenthesis y minus 3 right parenthesis squared equals 40 end cell row cell y equals negative 2 x plus 4 end cell end table
Which of the following could be the x-coordinate of a solution to the system of equations above?

  1. square root of 7
  2. fraction numerator square root of 35 over denominator 2 end fraction
  3. fraction numerator 6 plus 2 square root of 34 over denominator 5 end fraction
  4. fraction numerator 4 plus square root of 191 over denominator 5 end fraction

hintHint:

Hint:
To find the x co-ordinate, we first need to find the solution of the given system of equations. To solve these equations, we simply need to put the value of y from the second equation in the first equation. We get an equation in one variable x. This can be easily solved to get the value of the x coordinate which is x.
x squared plus 4 x plus 4 plus left parenthesis negative 2 x right parenthesis squared plus 2 times left parenthesis negative 2 x right parenthesis times 1 plus 1 equals 40

The correct answer is: square root of 7


    The given equations are
    table attributes columnspacing 1em end attributes row cell left parenthesis x plus 2 right parenthesis squared plus left parenthesis y minus 3 right parenthesis squared equals 40 end cell row cell y equals negative 2 x plus 4 end cell end table
    Putting the value of  from the second equation in the first, we get
    left parenthesis x plus 2 right parenthesis squared plus left curly bracket left parenthesis negative 2 x plus 4 right parenthesis minus 3 right curly bracket squared equals 40
    Applying the formula
    left parenthesis a plus b right parenthesis squared equals a squared plus 2 a b plus b squared
    We get,
    table attributes columnspacing 1em end attributes row cell open parentheses x squared plus 2.2 x plus 4 close parentheses plus left parenthesis negative 2 x plus 4 minus 3 right parenthesis squared equals 40 end cell row cell open parentheses x squared plus 4 x plus 4 close parentheses plus left parenthesis negative 2 x plus 1 right parenthesis squared equals 40 end cell end table
    Applying the formula  left parenthesis a plus b right parenthesis squared equals a squared plus 2 a b plus b squaredagain, we have
    Simplifying the above equation, we get
    x squared plus 4 x plus 4 plus 4 x squared minus 4 x plus 1 equals 40
    We add the co-efficient of terms which have the same degree of x.
    Bringing all the terms to the left hand side and solving for x, we get
    x squared plus 4 x plus 4 plus 4 x squared minus 4 x plus 1 equals 40
    Dividing by 5 on both sides, we have
    x squared equals 7

    Taking the positive square root both sides, we get
     

    Note:
    If we had to find the y-coordinate of the system of equations, then we put this value of x in the equation y equals negative 2 x plus 4 to get the value of y. Here, we got a quadratic equation of x, which did not have any term containing x, so it was easier to solve. If the quadratic equation was of the form  a x squared plus b c plus c equals 0, then we would use the quadratic formula  x equals fraction numerator negative b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction to solve the equation.

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