Maths-

General

Easy

Question

# 16 sin

- [-1,1]
- []
- []
- []

Hint:

### In this question, we have to find the range of 8 sin x.cos x.cos 2x.cos 4x.cos 8x. For that first we will simplify the trigonometric function and later as we know range of sin y and cos y is [-1,1], so, using this we can find the range of the given function.

## The correct answer is: [-1,1]

### f(x) = 8 sin x.co x.cos 2x.cos 4x.cos 8x

=4sin 2x.cos 4x.cos 8x

=2sin 8x.cos 8x

=sin 16x

So, range is [-1, 1].

### Related Questions to study

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According to Kirchhoff’s first law

(5A)+(4A)+(-3A)+(-5A)+I=0

Or I=-1A

(5A)+(4A)+(-3A)+(-5A)+I=0

Or I=-1A

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Maths-General

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period of sin ()=

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period of sin ()=

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Maths-General

f(x)=

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period of sin ()=

In denominator,

period of sin ()=

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period of sin ()=

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Similarly, for arms CF and FE, R’’=6

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Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

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Therefore, the 3 resistances in arm CD and DE are in series.

Similarly, for arms CF and FE, R’’=6

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R’’’=3

Now, R’’’ and 3 resistances are in parallel

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Substituting from Eq. (i), we get

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### The graph between the displacement and for a particle moving in a straight line is shown in figure. During the interval and the acceleration of the particle is

,

Region shows that graph bending toward time axis acceleration is negative.

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

### The graph between the displacement and for a particle moving in a straight line is shown in figure. During the interval and the acceleration of the particle is

,

Physics-General

Region shows that graph bending toward time axis acceleration is negative.

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero

Region shows that graph is parallel to time axis velocity is zero. Hence acceleration is zero.

Region shows that graph is bending towards displacement axis acceleration is positive.

Region shows that graph having constant slope velocity is constant. Hence acceleration is zero