Chemistry

Grade-9

Easy

Question

# 0.1g if carbon dioxide occupies a volume of 320cc at certain conditions. Under similar condition 0.2g of dioxide of element ‘X’ occupies 440cc. Calculate the atomic weight ‘X’.

- 34
- 39
- 32
- 38

## The correct answer is: 32

### According to the ideal gas equation, PV = nRT. Here,

V_{1} = 320 cc = 0.32 L

m of CO_{2} = 12 + 16 x 2 = 12 + 32 = 44

n_{1} = w/m = 0.1/44 gm = 0.0022

V2 = 440 cc = 0.44 L

Now, n_{2} = w/m

Hence, x = 34

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