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Question

There are 8 people in the lift. Few are ladies and the rest are children. Each lady weighs 150 pounds. Each child weighs 50 pounds. The total weight of the 8 people is 800 pounds. Construct the system of linear equations and use elimination method to solve.

hintHint:

let the no. of ladies in the lift be x and let the number of children  be y
Given total no. of people  = no. of ladies  + no. of children  = 8
Given total weight  = weight of x ladies + weight of y children = 800.

The correct answer is: 4


    Ans :- The no. of ladies in the lift are 4 and no. of children in the lift are 4 .
    Explanation :-
    Step 1:- construct the system of linear equations
    let the no. of ladies in the lift be x and let the number of children  be y
    Given total no. of people  = no. of ladies  + no. of children  = 8
    So, x + y = 8 — eq1
    Given total weight  = weight of x ladies + weight of y children = 800.
    weight of x ladies = x cross times weight of each lady ( Each lady weighs 150 pounds)
    weight of x ladies = 150x (pounds)
    weight of y children = y cross times weight of each child ( Each child weighs 50 pounds)
    weight of y children  = 50y (pounds)
    So total weight = 150x + 50y = 800 — eq2
    Step 2 :- eliminate x to find value of y
    Doing  eq2 - 150 cross timeseq1 to eliminate x
    We get 150x + 50y - 150 (x + y) = 800 - 150(8)
    not stretchy rightwards double arrow 50 y minus 150 y equals 800 minus 1200
    not stretchy rightwards double arrow negative 100 y equals negative 400 not stretchy rightwards double arrow y equals 4
    ∴ y = 4
    Step 3:- substitute the value of y in eq1 to get the value of x
    x plus y equals 8 not stretchy rightwards double arrow x plus 4 equals 8
    not stretchy rightwards double arrow x equals 8 minus 4
    ∴ x = 4
    ∴The no. of ladies in the lift are 4 and no. of children in the lift are 4 .

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