Maths-
General
Easy

Question

A man left half of a sum of money to his wife', one third of it to his son and the remainder to be divided equally between his twin daughters. lf each of his daughters received $8500' how much was the original sum of money?

Hint:

  • Hint:
○ Form the equation according to given information..
○ Take variable values as x or any alphabet.
○ Solve the equation to get value of x.

The correct answer is: $1,02,000.


    • Step by step explanation:
    ○ Given:
    rightwards double arrowman left half money to his wife,
    rightwards double arrowone third to his son.
    rightwards double arrowremaining money to twin daughters $8500 each.
    ○ Step 1:
    ○ Let us consider he has $x money.
    so,
    According to given situation
    rightwards double arrowwife got = 1 halfx
    rightwards double arrowson = 1 third x
    Hence,
    Twin sisters together will get

    rightwards double arrowx minus open parentheses 1 half x plus 1 third x close parentheses

    rightwards double arrow x minus open parentheses fraction numerator 3 plus 2 over denominator 6 end fraction x close parentheses

    rightwards double arrow x minus open parentheses 5 over 6 x close parentheses

    rightwards double arrow open parentheses fraction numerator 6 minus 5 over denominator 6 end fraction x close parentheses

    rightwards double arrow 1 over 6 x
    ○ Step 3:
    ○ Money twin sister got is (8500 + 8500) = 17000.

    1 over 6 x = 17000

    rightwards double arrowx = 17000 cross times 6

    rightwards double arrowx = 102000

    • Final Answer:
    Hence, original sum of money was $1,02,000.

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