Maths-
General
Easy

Question

Dimple Bought a Calculator and binder that were both 15% off the original price. The
original price of binder was Rs 6.20. Justin spent a total of Rs 107. 27 . What was the
original price of the calculator?

hintHint:

○ Form the equation using the given information.
○ Take variable quantity as x or any alphabet.
○ Percentage x of y is given by
not stretchy rightwards double arrow x over 100 cross times y

The correct answer is: Rs. 120


    ○ Given:
    Original price of binder = Rs.6.20
    Total money spent = Rs.107.27
    Discount  = 15% on  both
    ○ Step 1:
    ○ Find purchasing price of binder:
    It is given that original price of binder is Rs.6.20 and 15% discount is given
    So,
    The purchasing price of binder is:
    rightwards double arrow6.20 - 15% of 6.20
    rightwards double arrow6.20 -   6.20
    rightwards double arrow6.20 - 0.93
    rightwards double arrow5.27
    Purchasing price of binder = Rs. 5.27
    ○ Step 2:
    ○ Find purchasing price of calculator:
    It is given that total money spent is Rs.107.27
    So,
    rightwards double arrowPurchasing price of calculator + Purchasing price of binder = 107.27
    rightwards double arrowPurchasing price of calculator + 5.27 =  107.27
    rightwards double arrowPurchasing price of calculator  =  107.27 - 5.27
    rightwards double arrowPurchasing price of calculator  =  102
    Purchasing price of calculator is Rs. 102.
    ○ Step 3:
    ○ Find original price of calculator:
    ○ Let the original price of calculator be Rs. x.
    It is given that 15% discount is given on original price of calculator
    So,
    x - 15% of x = 102
    rightwards double arrowx - 15 over 100 space cross times x = 102
    rightwards double arrowfraction numerator 100 x space minus space 15 x over denominator 100 end fraction = 102
     85x = 102 cross times100
    rightwards double arrowx = 10200 over 85
     x = 120
    Original price of calculator is Rs. 120.
    • Final Answer:
    Hence, original price of calculator is Rs. 120..

    The x + 2 = 6 x+2=6x, plus, 2, equals 6 contains a variable. We call this type of equation with a variable an algebraic equation. Finding the variable value that will result in a true equation is typically our aim when solving an algebraic equation.
    ¶Variables or constants are the two types of measurable quantities. A variable is a quantity with a varying value, and the constant value is nothing but a constant.
    Steps to writing Variable Equation
    1) Identify the variables that represent the unknowns.
    2) Convert the issue into variable expressions in algebra.
    3) Determine the variables' values to solve the equations for their true values.

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