Question

# Dimple Bought a Calculator and binder that were both 15% off the original price. The

original price of binder was Rs 6.20. Justin spent a total of Rs 107. 27 . What was the

original price of the calculator?

Hint:

### ○ Form the equation using the given information.

○ Take variable quantity as x or any alphabet.

○ Percentage x of y is given by

## The correct answer is: Rs. 120

### ○ Given:

Original price of binder = Rs.6.20

Total money spent = Rs.107.27

Discount = 15% on both

○ Step 1:

○ Find purchasing price of binder:

It is given that original price of binder is Rs.6.20 and 15% discount is given

So,

The purchasing price of binder is:

6.20 - 15% of 6.20

6.20 - 6.20

6.20 - 0.93

5.27

Purchasing price of binder = Rs. 5.27

○ Step 2:

○ Find purchasing price of calculator:

It is given that total money spent is Rs.107.27

So,

Purchasing price of calculator + Purchasing price of binder = 107.27

Purchasing price of calculator + 5.27 = 107.27

Purchasing price of calculator = 107.27 - 5.27

Purchasing price of calculator = 102

Purchasing price of calculator is Rs. 102.

○ Step 3:

○ Find original price of calculator:

○ Let the original price of calculator be Rs. x.

It is given that 15% discount is given on original price of calculator

So,

x - 15% of x = 102

x - x = 102

= 102

85x = 102 100

x =

x = 120

Original price of calculator is Rs. 120.

- Final Answer:

Hence, original price of calculator is Rs. 120..

The x + 2 = 6 x+2=6x, plus, 2, equals 6 contains a variable. We call this type of equation with a variable an algebraic equation. Finding the variable value that will result in a true equation is typically our aim when solving an algebraic equation.

¶Variables or constants are the two types of measurable quantities. A variable is a quantity with a varying value, and the constant value is nothing but a constant.

¶**Steps to writing Variable Equation**

1) Identify the variables that represent the unknowns.

2) Convert the issue into variable expressions in algebra.

3) Determine the variables' values to solve the equations for their true values.