Maths-
General
Easy

Question

Use the Law of Syllogism to write a new conditional statement that follows from the pair of true statements.
If an element is in set A, then it is in set B.
If an element is in set C, then it is in set A.

hintHint:

Law of Syllogism states that:
1) if p not stretchy rightwards arrow  q is true
2) If q not stretchy rightwards arrow r is true
then we can conclude that p space not stretchy rightwards arrow r is also true.

The correct answer is: Hence, the new conditional statement is “If an element is in set C, then it is in set B”.


    It is given that: If an element is in set A, then it is in set B and If an element is in set C, then it is in 
    set A. So if we take
    p = Element is in set C
    q = Element is in set A
    r = Element is in set B
    So can write the given statement “If an element is in set C, then it is in set A” as p not stretchy rightwards arrow q and the
    statement “If an element is in set A, then it is in set B” can be written as q  not stretchy rightwards arrow r.
    So, we can conclude that p  not stretchy rightwards arrow r which means that If an element is in set C, then it is in set B.
    Final Answer:
    Hence, the new conditional statement is “If an element is in set C, then it is in set B”.

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