Graph f(x) = -0.75x² + 3x - 4. What are axis of symmetry, vertex and y-intercept of the function

The correct answer is: -4

                         

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= -0.75x²+3x-4, a= -0.75, b=3, and c= - 4. So, the equation for the axis of symmetry is given by
x = −(3)/2(-0.75)
x = 3/1.5
x = 2
The equation of the axis of symmetry for f(x)=-0.75x²+3x-4 is x = 2.
The x coordinate of the vertex is the same:
h = 2
The y coordinate of the vertex is :
k = f(h)
k = -0.75(h)² + 3(h) - 4
k = -0.75(2)² + 3(2) - 4
k = -3 + 6 - 4
k = -1
Therefore, the vertex is (2 , -1)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.
y = -0.75(0)² + 3(0) - 4
y = 0 + 0 - 4
y = -4
Therefore, Axis of symmetry is x = 2
Vertex is ( 2, -1 )
Y- intercept is -4.