Maths
General
Easy
Question
If the point (2a, a) lies inside the parabola x^{2} – 2x – 4y + 3 = 0, then a lies in the interval 


 (1, 3)

Hint:
If f(x,y) = 0 is the equation of parabola with axis parallel to x axis and point (a,b) be a point inside parabola then f(a,b) < 0.
The correct answer is:
If f(x,y) =x2 – 2x – 4y + 3 = 0 is the equation of parabola with axis parallel to x axis and point (a,b) be a point inside parabola then f(a,b) < 0.
Then f(2a,a) < 0
(2a)^{2} – 2(2a) – 4(a) + 3 < 0
4a^{2}  8a + 3 < 0
(2a1)(2a3) < 0 then a lies in .
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