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# Internal length, height, and breadth of an open box are 95 cm, 82 cm, and 75 cm. Thickness of wood is given to be 2.5 cm, calculate the cost of painting outside the box as Rs 1 per dm^{2}

- 458.20
- 386.20
- 626.20
- 384.20

Hint:

### Total Surface Area(TSA) of cuboid = 2[ lb + bh + hl ]

Where,

l = length

b = breadth

h = height

We have to add the thickness of wood on both sides for finding the outside dimensions.

## The correct answer is: 384.20

### We have given the Internal dimensions of the box

length = 95 cm,

breadth = 75 cm

height = 82 cm

Outer dimensions of the box are

length = 95 + 2 2.5 = 100 cm,

breadth = 75 + 2 2.5 = 80 cm

height = 82 + 2.5 = 84.5 --as the box is open we will add only 2.5

Surface area of the box = 2(lb+ bh +lh)

= 2((95)(75)+(75)(82)+(95)(82))

= 2(8000+6760+8450)=

= 46420 cm^{2}

Surface area of the open box = Total area - area of open side

= 46420 – (95)(75)

= 46420-8000

= 38420 cm^{2}

= 384.2 dm^{2}

Cost of painting = Rs. 384.20

Therefore option d) 384.20 is correct.

^{2}

Surface area of the open box = Total area - area of open side

^{2}

^{2}

Therefore option d) 384.20 is correct.

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