Question

# The cross section of a piece of a metal 2m in length is shown below. Find area of cross section and volume of piece of metal in cubic meters

- 57 , 11400
- 57, 12410
- 75,11400
- 75,12410

## The correct answer is: 75,12410

### Related Questions to study

### The figure alongside shows the cross-section of a concrete wall to be constructed. It is 3m wide at the top, 5.5 m wide at the bottom and its height is 10 m and its length is 500m.Calculate

(i) the cross-sectional area

### The figure alongside shows the cross-section of a concrete wall to be constructed. It is 3m wide at the top, 5.5 m wide at the bottom and its height is 10 m and its length is 500m.Calculate

(i) the cross-sectional area

### A teak wood log first cut in the form of a cuboid of length 2.3 m, width 0.75 m and of certain thickness. Its volume is of 1.004m^3. How many rectangular planks of size 2.3m x 0.75m x 0.04m can be cut from the cuboid

Length l = 2.3 m

Breadth b = 0.75

Its volume = 1.004 m^3

We have to find thickness h.

And planks dimensions are

Length = 2.3

Breadth = 0.75

Thickness = 0.04

Volume of wood log = l b h

1.004 = 2.3 0.75 h

1.004 = 1.725 h

h = 1.004/ 1.725

h = 0.5820

As the length and breadth are the same for both log and plank then we should divide the height by thickness of the plank so we will get number of planks.

No of planks = 0.5820/ 0.04

= 14.55

~ 14

Therefore the correct answer is b) 14.

### A teak wood log first cut in the form of a cuboid of length 2.3 m, width 0.75 m and of certain thickness. Its volume is of 1.004m^3. How many rectangular planks of size 2.3m x 0.75m x 0.04m can be cut from the cuboid

Length l = 2.3 m

Breadth b = 0.75

Its volume = 1.004 m^3

We have to find thickness h.

And planks dimensions are

Length = 2.3

Breadth = 0.75

Thickness = 0.04

Volume of wood log = l b h

1.004 = 2.3 0.75 h

1.004 = 1.725 h

h = 1.004/ 1.725

h = 0.5820

As the length and breadth are the same for both log and plank then we should divide the height by thickness of the plank so we will get number of planks.

No of planks = 0.5820/ 0.04

= 14.55

~ 14

Therefore the correct answer is b) 14.

### The cross-section of a swimming pool is a trapezium ABCD. AB=12m CD= 13 m DA= 5 m and the length of the pool is 60 m. Find the volume of water it holds?

### The cross-section of a swimming pool is a trapezium ABCD. AB=12m CD= 13 m DA= 5 m and the length of the pool is 60 m. Find the volume of water it holds?

### A metal cube with a 6 cm edge is melted and cast into a cuboid whose base is 3.60x 0.60 cm^{2} .Calculate the height of the cuboid. Also, find the total surface area of the cuboid and cube respectively

Dimensions of cuboid

Length l = 3.60

Breadth b = 0.60

We have to find the height of the cuboid h.

As the both solids have same amount of material their volume will be same

l x b x h = a^{3}

3.60 x 0.60 x h = 6^{3}

2.16 x h = 216

Dividing both sides by 2.16 we get,

h = 100

TSA of cube = 6a^{2}

= 6(6)^{2}

= 6(36)

= 216 sq.cm

TSA of cuboid = 2[lb + bh + hl]

= 2[(3.60)(0.60) + (0.60)(100) + (100)(3.60)]

= 2[ 2.16 + 60 + 360 ]

= 2[ 422.16 ]

= 844.32 sq.cm

Therefore, the correct option is c) 844.32 cm^{2} and 216 cm^{2}.

### A metal cube with a 6 cm edge is melted and cast into a cuboid whose base is 3.60x 0.60 cm^{2} .Calculate the height of the cuboid. Also, find the total surface area of the cuboid and cube respectively

Dimensions of cuboid

Length l = 3.60

Breadth b = 0.60

We have to find the height of the cuboid h.

As the both solids have same amount of material their volume will be same

l x b x h = a^{3}

3.60 x 0.60 x h = 6^{3}

2.16 x h = 216

Dividing both sides by 2.16 we get,

h = 100

TSA of cube = 6a^{2}

= 6(6)^{2}

= 6(36)

= 216 sq.cm

TSA of cuboid = 2[lb + bh + hl]

= 2[(3.60)(0.60) + (0.60)(100) + (100)(3.60)]

= 2[ 2.16 + 60 + 360 ]

= 2[ 422.16 ]

= 844.32 sq.cm

Therefore, the correct option is c) 844.32 cm^{2} and 216 cm^{2}.

### Determine if the given conjecture is true or not. Give a counterexample if it is false.

Given: ∠𝑃 𝑎𝑛𝑑 ∠𝑄 are complementary. ∠𝑄 𝑎𝑛𝑑 ∠𝑅 are complementary.

Conjecture: ∠𝑃 ≅ ∠𝑅

∠𝑃 𝑎𝑛𝑑 ∠𝑄 are complementary.

∠𝑄 𝑎𝑛𝑑 ∠𝑅 are complementary.

Which means ∠𝑃 + ∠𝑄 = 90

And ∠𝑄 + ∠𝑅 = 90

If we subtract ∠𝑄 from both sides of both equations we get,

∠P =90 - ∠𝑄

∠R = 90 - ∠𝑄

If we compare RHS of the both obtained equations

We can say that

∠𝑃 ≅ ∠𝑅

Therefore, the given conjecture is true.

### Determine if the given conjecture is true or not. Give a counterexample if it is false.

Given: ∠𝑃 𝑎𝑛𝑑 ∠𝑄 are complementary. ∠𝑄 𝑎𝑛𝑑 ∠𝑅 are complementary.

Conjecture: ∠𝑃 ≅ ∠𝑅

∠𝑃 𝑎𝑛𝑑 ∠𝑄 are complementary.

∠𝑄 𝑎𝑛𝑑 ∠𝑅 are complementary.

Which means ∠𝑃 + ∠𝑄 = 90

And ∠𝑄 + ∠𝑅 = 90

If we subtract ∠𝑄 from both sides of both equations we get,

∠P =90 - ∠𝑄

∠R = 90 - ∠𝑄

If we compare RHS of the both obtained equations

We can say that

∠𝑃 ≅ ∠𝑅

Therefore, the given conjecture is true.

### A plate of 3 cm thick, 9 cm broad, and 27 m long is melted into a cube. find the difference in surface area of the two solids correct to the nearest whole number.

Thickness h = 3 cm

Breadth b= 9cm

Length l = 27cm

This plate is melted into cube , let x be the length of side of cube

So, as the plate is melted into cube the volume of both the solids will be same

Therefore, l x b x h = x

^{3}

27 x 9 x 3 = x^{3}

729 = x^{3}

As we know, 729 is the cube of 9

Therefore, x = 9

Surface area of the plate = 2[lb + bh + hl]

= 2[(27)(9) + (9)(3) + (3)(27)]

= 2[243 + 27 + 81]

= 2(351)

= 702

Surface area of the cube = 6x^{2}

= 6(9)^{2}

= 6 (81)

= 486

Difference between both the areas= 702 – 486

= 216

Therefore the difference between the volumes is surface area .

### A plate of 3 cm thick, 9 cm broad, and 27 m long is melted into a cube. find the difference in surface area of the two solids correct to the nearest whole number.

Thickness h = 3 cm

Breadth b= 9cm

Length l = 27cm

This plate is melted into cube , let x be the length of side of cube

So, as the plate is melted into cube the volume of both the solids will be same

Therefore, l x b x h = x

^{3}

27 x 9 x 3 = x^{3}

729 = x^{3}

As we know, 729 is the cube of 9

Therefore, x = 9

Surface area of the plate = 2[lb + bh + hl]

= 2[(27)(9) + (9)(3) + (3)(27)]

= 2[243 + 27 + 81]

= 2(351)

= 702

Surface area of the cube = 6x^{2}

= 6(9)^{2}

= 6 (81)

= 486

Difference between both the areas= 702 – 486

= 216

Therefore the difference between the volumes is surface area .

### Which number is next in the sequence?

35, 85, 135, 185, __

a

_{n}= a + (n – 1) × d

Solution :- We have given the pattern of numbers

35, 85, 135, 185, __

We have to find the next number.

We can see clearly that it is an Arithmetic progression With Common difference = 85 - 35 = 50

= 135 - 85 = 50

= 185 - 135 = 50

Therefore next term will be

185 + Common difference

185 + 50 = 235

Therefore, the pattern will be

35, 85, 135, 185, 235

### Which number is next in the sequence?

35, 85, 135, 185, __

a

_{n}= a + (n – 1) × d

Solution :- We have given the pattern of numbers

35, 85, 135, 185, __

We have to find the next number.

We can see clearly that it is an Arithmetic progression With Common difference = 85 - 35 = 50

= 135 - 85 = 50

= 185 - 135 = 50

Therefore next term will be

185 + Common difference

185 + 50 = 235

Therefore, the pattern will be

35, 85, 135, 185, 235

### A cuboidal water tank is 6m long , 5m wide and 4.5 m deep.

How many litres of water can it hold ?

The given cuboidal water tank has-

- Length = 6m,
- Width = 5m and
- Height = 4.5m

Volume of a cuboid = Length * Width * Height

∴ Volume of the cuboidal tank = 6 * 5 * 4.5

∴ Volume of the cuboidal tank = 135 m3.

Now, we know that-

1 = 1,000 L

∴ 135 = 1,000 * 135

∴ 135 = 1,35,000 L.

### A cuboidal water tank is 6m long , 5m wide and 4.5 m deep.

How many litres of water can it hold ?

The given cuboidal water tank has-

- Length = 6m,
- Width = 5m and
- Height = 4.5m

Volume of a cuboid = Length * Width * Height

∴ Volume of the cuboidal tank = 6 * 5 * 4.5

∴ Volume of the cuboidal tank = 135 m3.

Now, we know that-

1 = 1,000 L

∴ 135 = 1,000 * 135

∴ 135 = 1,35,000 L.

### Show the conjecture is false by finding a counterexample.

Two supplementary angles form a linear pair.

Given, two supplementary angles always form a liner pair

We have to determine if the given statement is true or false.

When the sum of measures of two angles is 180 degrees, then the angles are called supplementary angles.

When two lines intersect each other at a single point, linear pairs of angles are formed.

From the figure,

∠1 + ∠2 = 180°

Linear pair of angles occurs in a straight line.

So, two supplementary angles do not always form a linear pair.

Therefore, the given statement is false.

### Show the conjecture is false by finding a counterexample.

Two supplementary angles form a linear pair.

Given, two supplementary angles always form a liner pair

We have to determine if the given statement is true or false.

When the sum of measures of two angles is 180 degrees, then the angles are called supplementary angles.

When two lines intersect each other at a single point, linear pairs of angles are formed.

From the figure,

∠1 + ∠2 = 180°

Linear pair of angles occurs in a straight line.

So, two supplementary angles do not always form a linear pair.

Therefore, the given statement is false.

### Show the conjecture is false by finding a counterexample.

Two adjacent angles always form a linear pair

Two adjacent angles always form a linear pair.

We have to prove the statement is false.

The linear pair of angles is a pair of angles which is created by the intersection of two straight lines and the sum of a linear pair of angles is 180°.

Now, if we take an angle which is less than 180° and bisect that angle with the help of a straight line, then we will get two adjacent angles. And, the sum of those two adjacent angles isn't 180°.

In this way, we can come to a conclusion that every pair of adjacent angles will be not considered as the linear pair of angles.

So, the given conjecture is false.

### Show the conjecture is false by finding a counterexample.

Two adjacent angles always form a linear pair

Two adjacent angles always form a linear pair.

We have to prove the statement is false.

The linear pair of angles is a pair of angles which is created by the intersection of two straight lines and the sum of a linear pair of angles is 180°.

Now, if we take an angle which is less than 180° and bisect that angle with the help of a straight line, then we will get two adjacent angles. And, the sum of those two adjacent angles isn't 180°.

In this way, we can come to a conclusion that every pair of adjacent angles will be not considered as the linear pair of angles.

So, the given conjecture is false.

### A cubical tank 50 cm in length and 36 cm in breadth contain water. A cube of x cm edge is dropped into it and fully immersed. If the rise in water level is 15 cm, solve for x. and hence find the T.S.A of the cubical tank

Length l = 50cm

Breadth b= 36cm

The dimensions of cube dropped are

Side = x cm

We have to find the value of x and TSA of cubical tank.

It is given that rise in water level is 15 cm , so it will be the height of the water in the cubical tank

h = 15 cm

Therefore the volume of the cube dropped will be

Volume = l b h

x^{3} = 50 36 15

= 27000

As 27000 is a cube of 30

x^{3 }= (30)^{3}

therefore, x = 30

The TSA of the cubical tank = 2[lb + bh + hl]

= 2[(50)(36) + (36)(15) + (15)(50)l]

= 2[1800 + 540 + 750]

= 2[3090]

= 6180

Which is approximately equal to 6200.

Therefore, the correct option is a) 30 , 6200.

### A cubical tank 50 cm in length and 36 cm in breadth contain water. A cube of x cm edge is dropped into it and fully immersed. If the rise in water level is 15 cm, solve for x. and hence find the T.S.A of the cubical tank

Length l = 50cm

Breadth b= 36cm

The dimensions of cube dropped are

Side = x cm

We have to find the value of x and TSA of cubical tank.

It is given that rise in water level is 15 cm , so it will be the height of the water in the cubical tank

h = 15 cm

Therefore the volume of the cube dropped will be

Volume = l b h

x^{3} = 50 36 15

= 27000

As 27000 is a cube of 30

x^{3 }= (30)^{3}

therefore, x = 30

The TSA of the cubical tank = 2[lb + bh + hl]

= 2[(50)(36) + (36)(15) + (15)(50)l]

= 2[1800 + 540 + 750]

= 2[3090]

= 6180

Which is approximately equal to 6200.

Therefore, the correct option is a) 30 , 6200.

### Show the conjecture is false by finding a counterexample.

If the product of two numbers is even, then the two numbers must be even.

We have given a statement

If the product of two numbers is even, then the two numbers must be even.

We have to show the given conjecture is false.

Let us take two even numbers 6 and 8

Product of considered numbers = 6 x 8 = 48

Product we get is an even number , so the given statement is true for considered values.

If we consider one odd and one even number , 5 and 6

Product = 5 x 6 = 30

So, the product obtained is an even which contradicts the given statement

So, We can say that if the product of two numbers is even, then the two numbers need be even.

So, the given conjecture is false.

### Show the conjecture is false by finding a counterexample.

If the product of two numbers is even, then the two numbers must be even.

We have given a statement

If the product of two numbers is even, then the two numbers must be even.

We have to show the given conjecture is false.

Let us take two even numbers 6 and 8

Product of considered numbers = 6 x 8 = 48

Product we get is an even number , so the given statement is true for considered values.

If we consider one odd and one even number , 5 and 6

Product = 5 x 6 = 30

So, the product obtained is an even which contradicts the given statement

So, We can say that if the product of two numbers is even, then the two numbers need be even.

So, the given conjecture is false.

### Show the conjecture is false by finding a counterexample.

If a + b = 0, then a = b = 0.

We have given a statement

If a + b = 0, then a = b = 0

We have to show the given conjecture is false.

Let us take a = 0 and b = 0

Then a + b = 0 + 0 = 0

Given statement is true for considered values of a and b.

Let us take a = 3 and b = - 3

Then a + b = 3 + (- 3) = 3 – 3 = 0

From this example we can say that it is not necessary that and b should be 0 to get sum of a and b to be 0 .

Therefore, the given conjecture is false.

### Show the conjecture is false by finding a counterexample.

If a + b = 0, then a = b = 0.

We have given a statement

If a + b = 0, then a = b = 0

We have to show the given conjecture is false.

Let us take a = 0 and b = 0

Then a + b = 0 + 0 = 0

Given statement is true for considered values of a and b.

Let us take a = 3 and b = - 3

Then a + b = 3 + (- 3) = 3 – 3 = 0

From this example we can say that it is not necessary that and b should be 0 to get sum of a and b to be 0 .

Therefore, the given conjecture is false.

### calculate the surface area of a cube and volume of a cube with the given diagonal length of 15cm

D= 15 cm

We have to find the Surface area and volume of the cube.

We know that Diagonal of the cube = a

Where a is side of the cube

Comparing with the given value we get

a = 15 cm

Therefore , Surface area of cube = 6a^{2}

= 6(15)^{2}

= 6(225)

= 1350

And, volume of the given cube = a^{3}

= (15)^{3}

= 3375

Therefore the correct option is c)1350, 3375.

### calculate the surface area of a cube and volume of a cube with the given diagonal length of 15cm

D= 15 cm

We have to find the Surface area and volume of the cube.

We know that Diagonal of the cube = a

Where a is side of the cube

Comparing with the given value we get

a = 15 cm

Therefore , Surface area of cube = 6a^{2}

= 6(15)^{2}

= 6(225)

= 1350

And, volume of the given cube = a^{3}

= (15)^{3}

= 3375

Therefore the correct option is c)1350, 3375.

### Show the conjecture is false by finding a counterexample.

If the product of two numbers is positive, then the two numbers must both be positive.

Solution:-

We have given a statement If the product of two numbers is positive, then the two numbers must both be positive.

If we consider two positive numbers 7 and 9

Then , their product, 7 x 9 = 63

Hence, the statement is correct for positive integers

Suppose we take two negative integers - 7 and - 9

Then, their product, - 7 x - 9 = 63

So,The product of any two positive numbers is positive, and the product of any two negative numbers is also positive.

Therefore, the given statement is false.

### Show the conjecture is false by finding a counterexample.

If the product of two numbers is positive, then the two numbers must both be positive.

Solution:-

We have given a statement If the product of two numbers is positive, then the two numbers must both be positive.

If we consider two positive numbers 7 and 9

Then , their product, 7 x 9 = 63

Hence, the statement is correct for positive integers

Suppose we take two negative integers - 7 and - 9

Then, their product, - 7 x - 9 = 63

So,The product of any two positive numbers is positive, and the product of any two negative numbers is also positive.

Therefore, the given statement is false.