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Maths-

General

Easy

Question

What is the length of the longest pole that can be fit in the room of dimensions 5m x 10m x 5m

12.25
11.95
12.85
11.85

hint Hint:

Diagonal of cube= $square root of 3$ × side = $square root of 3$ a unit

The correct answer is: 12.25

The dimensions of the room are
Length = 5m
Breadth = 10m
Height = 5m
We know that
Length of the longest pole = length of diagonal = $square root of open parentheses l squared plus b squared plus h squared close parentheses end root$
By substituting the values
Length of the longest pole = $square root of open parentheses 5 squared plus 10 squared plus 5 squared close parentheses end root$
So we get
Length of the longest pole = $square root of blank end root left parenthesis 25 plus 100 plus 25 right parenthesis$
By addition
Length of the longest pole = $square root of 150 equals 12.25 straight m$
Therefore, the length of the longest pole that can be put in the room is 12.25m.
The correct option is a)12.25.

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