Physics-
General
Easy

Question

4 eV is the energy of the incident photon and the work function in 2 e V. What is the stopping potential

  1. 2V    
  2. 4V    
  3. 6V    
  4. 2 square root of 2 V    

The correct answer is: 2V


    E equals W subscript 0 end subscript plus e V subscript 0 end subscript rightwards double arrow 4 e V equals 2 e V plus e V subscript 0 end subscript rightwards double arrow V subscript 0 end subscript equals 2   v o l t

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    f(x)=open curly brackets table row cell fraction numerator e to the power of a x end exponent minus e to the power of x end exponent minus x over denominator x to the power of 2 end exponent end fraction blank comma end cell cell x not equal to 0 end cell row cell fraction numerator 3 over denominator 2 end fraction blank comma end cell cell x equals 0 end cell end table close , the value of ‘a’ so that f is continuous function is

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