Physics
Grade-9
Easy

Question

An oven consumes 525 kWh of energy to provide 386 kWh of useful energy. What is its percentage efficiency?

  1. 73
  2. 73.5
  3. 74
  4. 90.5

hintHint:

  • Efficiency (%) = (useful energy output ÷ energy input) × 100

The correct answer is: 73.5


    • Efficiency (%) = (useful energy output ÷ energy input) × 100
    • E f f i c i e n c y equals 386 over 525 cross times 100 equals 73.5

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