Physics
Grade-8
Easy

Question

There are two cars, car A and car B. Mass of car A is 2000 kg, travelling at 30 fraction numerator m over denominator s end fraction collide with car B of mass 3000 kg travelling at 40 fraction numerator m over denominator s end fraction in same direction. After collision, the velocity of car A becomes 50 fraction numerator m over denominator s end fraction. Calculate the velocity of car B after the collision?

  1. fraction numerator 80 over denominator 3 end fraction fraction numerator m over denominator s end fraction    
  2. fraction numerator 3 over denominator 80 end fraction fraction numerator m over denominator s end fraction    
  3. fraction numerator 83 over denominator 3 end fraction fraction numerator m over denominator s end fraction    
  4. fraction numerator 77 over denominator 3 end fraction fraction numerator m over denominator s end fraction    

hintHint:

  • The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.

The correct answer is: fraction numerator 80 over denominator 3 end fraction fraction numerator m over denominator s end fraction


    • The formula for the law of conservation of momentum is: m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2.
    • 2000 cross times 30 plus 3000 cross times 40 equals 2000 cross times 50 plus 3000 v 2
s o space v 2 equals 80 over 3 space m divided by s

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