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Physics

Grade-9

Easy

Question

Two simple pendulums of lengths 5 m and 20 m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed .... oscillations.

3
5
2
1

hint Hint:

$T equals 2 pi square root of l over g end root$

The correct answer is: 2

It is given that,
Length of first pendulum, l1=5m
Length of second pendulum,l2=20m
Time period is given by: $T equals 2 pi square root of l over g end root$
So T1=
$2 pi square root of fraction numerator l 1 over denominator g end fraction end root equals 2 pi square root of 5 over 10 end root equals 2 pi square root of 1 half end root a l s o space 2 pi square root of fraction numerator l 2 over denominator g end fraction end root equals 2 pi square root of 20 over 10 end root equals 2 pi square root of 2 s o space T 1 equals square root of 2 space pi T 2 equals 2 square root of 2 pi T 2 space space space equals 2 T 1 space space space space T h e space v a l u e space o f space n space i s space 2$

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