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A convex kens of focal length f is placed somewhere in between an object and a screen. The distance between the object and the screen is  x. If the numerical value of the magnification product by the lens is m , What is the focal length of the lens?

  1. fraction numerator m x over denominator open parentheses m minus 1 close parentheses squared end fraction
  2. fraction numerator m x over denominator open parentheses m plus 1 close parentheses squared end fraction
  3. open parentheses m minus 1 close parentheses squared over m x
  4. left parenthesis m plus 1 right parenthesis squared over m x

The correct answer is: fraction numerator m x over denominator open parentheses m plus 1 close parentheses squared end fraction

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