Question
Match the types of WBC listed under Column - I with the shape of nucleus given under Column - II and select the correct option from codes given below.

- (a)
(iii), (b)
(iv), (c)
(i), (d)
(ii)
- (a)
(v), (b)
(iii), (c)
(i), (d)
(iv)
- (a)
(ii), (b)
(i), (c)
(v), (d)
(iii)
- (a)
(iii), (b)
(iv), (c)
(ii), (d)
(i)
The correct answer is: (a)
(iii), (b)
(iv), (c)
(ii), (d)
(i)
Related Questions to study
The number of ways in which four letters can put in four addressed envelopes so that no letter goes into the envelope meant for it is :
Now, number of ways of putting only 1 letter in the right envelope=
number of ways of putting only 2 letters in the right envelopes =
number of ways of putting 3 letters in the right envelope= 0, as when we will put three letters in the right envelope the last will automatically go in the right place.
number of ways of putting 4 letters in the right envelope= 1
So, the number of ways in which four letters can put in four addressed envelopes so that no letter goes into the envelope meant for it =24-(8+6+0+1)=24-15=9
The number of ways in which four letters can put in four addressed envelopes so that no letter goes into the envelope meant for it is :
Now, number of ways of putting only 1 letter in the right envelope=
number of ways of putting only 2 letters in the right envelopes =
number of ways of putting 3 letters in the right envelope= 0, as when we will put three letters in the right envelope the last will automatically go in the right place.
number of ways of putting 4 letters in the right envelope= 1
So, the number of ways in which four letters can put in four addressed envelopes so that no letter goes into the envelope meant for it =24-(8+6+0+1)=24-15=9
In the given figure of the heart which of the labelled part (1, 2, 3, 4, 5) carries oxygenated blood?

In the given figure of the heart which of the labelled part (1, 2, 3, 4, 5) carries oxygenated blood?

The given figure shows an angiogram of the coronary blood vessel. Which one of the following statements correctly describes, what is being done?

The given figure shows an angiogram of the coronary blood vessel. Which one of the following statements correctly describes, what is being done?

There are 3 letters and 3 addressed envelopes corresponding to them. The number of ways in which the letters be placed in the envelopes so that no letter is in the right envelope is:
now, numbers of ways when only 1 letter is put in the right envelope =
number of ways when 2 letters are put in the right envelope = 0
as when we put 2 letters in the right envelope the third letter would be automatically in the right envelope
number of ways when 3 letters are put in the right envelope = 1
So, the no. of ways when no letter will be in the right envelope=6-(3+0+1) =6-4 =2
There are 3 letters and 3 addressed envelopes corresponding to them. The number of ways in which the letters be placed in the envelopes so that no letter is in the right envelope is:
now, numbers of ways when only 1 letter is put in the right envelope =
number of ways when 2 letters are put in the right envelope = 0
as when we put 2 letters in the right envelope the third letter would be automatically in the right envelope
number of ways when 3 letters are put in the right envelope = 1
So, the no. of ways when no letter will be in the right envelope=6-(3+0+1) =6-4 =2
Match Column - I with Column - II and select the correct option from the codes give below.

Match Column - I with Column - II and select the correct option from the codes give below.

The sum of all the numbers formed by taking all the digits from 3,4,5,6,7 is:
The number of numbers having 4 in the unit place= 4! =24
The number of numbers having 5 in the unit place= 4! =24
The number of numbers having 6 in the unit place= 4! =24
The number of numbers having 7 in the unit place= 4! =24
So the sum of the digits in the unit place of all the numbers=
=24(3+4+5+6+7)
=24
Similarly the sum of the digits of all the numbers in each of the other places=600
The required sum =
=600(10000+1000+100+10+1)
=600(11111)
=6666600
The sum of all the numbers formed by taking all the digits from 3,4,5,6,7 is:
The number of numbers having 4 in the unit place= 4! =24
The number of numbers having 5 in the unit place= 4! =24
The number of numbers having 6 in the unit place= 4! =24
The number of numbers having 7 in the unit place= 4! =24
So the sum of the digits in the unit place of all the numbers=
=24(3+4+5+6+7)
=24
Similarly the sum of the digits of all the numbers in each of the other places=600
The required sum =
=600(10000+1000+100+10+1)
=600(11111)
=6666600
The sum of all the numbers formed by taking all the digits from 2,3,4,5 is:
The number of numbers having 3 in the unit place= 3! =6
The number of numbers having 4 in the unit place= 3! =6
The number of numbers having 5 in the unit place= 3! =6
So the sum of the digits in the unit place of all the numbers=
=12+18+24+30
=84
Similarly the sum of the digits of all the numbers in each of the other places=84
The required sum =
=84(1000+100+10+1)
=84
=93324
The sum of all the numbers formed by taking all the digits from 2,3,4,5 is:
The number of numbers having 3 in the unit place= 3! =6
The number of numbers having 4 in the unit place= 3! =6
The number of numbers having 5 in the unit place= 3! =6
So the sum of the digits in the unit place of all the numbers=
=12+18+24+30
=84
Similarly the sum of the digits of all the numbers in each of the other places=84
The required sum =
=84(1000+100+10+1)
=84
=93324
The number of constant mappings from
to
is
The number of constant mappings from
to
is
The number of many one functions from
is
Element A can have an image in 3 ways, i.e., (1, 2, 3)
Similarly, B can have an image in 4 ways.
Thus, total number of ways =4×4×4=64
The number of many one functions from
is
Element A can have an image in 3 ways, i.e., (1, 2, 3)
Similarly, B can have an image in 4 ways.
Thus, total number of ways =4×4×4=64
The number of into functions that can be defined from
is
The number of into functions that can be defined from
is
A body moving with velocity v has momentum and kinetic energy numerically equal. What is the value of v?
A body moving with velocity v has momentum and kinetic energy numerically equal. What is the value of v?
The graph between the resistive force F acting on a body and the distance covered by the body is shown in figure. The mass of the body is 25KG and initial velocity is 2 m/s. When the distance covered by the body is 4km, its kinetic energy would be
The graph between the resistive force F acting on a body and the distance covered by the body is shown in figure. The mass of the body is 25KG and initial velocity is 2 m/s. When the distance covered by the body is 4km, its kinetic energy would be
The number of onto functions that can be defined from A={a,b,c,d,e} to {1,2} is
Given, A= {a, b, c, d, e} and B= {1 ,2}
Element a can has an image in 2 ways, i.e., (1 or 2).
Similarly, a, b, c, d and e can have an image in 5 ways.
Thus, total number of ways =2×2×2×2×2=32
The number of onto functions that can be defined from A={a,b,c,d,e} to {1,2} is
Given, A= {a, b, c, d, e} and B= {1 ,2}
Element a can has an image in 2 ways, i.e., (1 or 2).
Similarly, a, b, c, d and e can have an image in 5 ways.
Thus, total number of ways =2×2×2×2×2=32
The momentum of a body increases by 20%. The percentage increase in its kinetic energy is
The momentum of a body increases by 20%. The percentage increase in its kinetic energy is
Two spheres A and B of masses M1 and M2 respectively collide. A is at rest initially and B is moving with velocity V along X-axis. After collision has a velocity in a direction perpendicular to the original direction. The mass moves after collision in the direction
Two spheres A and B of masses M1 and M2 respectively collide. A is at rest initially and B is moving with velocity V along X-axis. After collision has a velocity in a direction perpendicular to the original direction. The mass moves after collision in the direction