The ultimate source of organic evolution is-Turito

General

Easy

Biology

The ultimate source of organic evolution is

BiologyGeneral

Natural selection
Sexual reproduction
Hormonal action
Mutations

Answer:The correct answer is: Mutations

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General

maths-

If $a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript horizontal ellipsis horizontal ellipsis horizontal ellipsis a subscript n end subscript$ are in A.P with common difference $d$ then sind $open square brackets c o s e c invisible function application a subscript 1 end subscript c o s e c invisible function application a subscript 2 end subscript plus close$ $c o s e c invisible function application a subscript 2 end subscript c o s e c invisible function application a subscript 3 end subscript plus c o s e c invisible function application a subscript 3 end subscript c o s e c invisible function application a subscript 4 end subscript plus horizontal ellipsis horizontal ellipsis n$ terms] $equals$

maths-General

General

maths-

The sum of all integers between 50 and 500 which are divisible by 7 is

maths-General

General

maths-

$left parenthesis 666 horizontal ellipsis text n digits end text right parenthesis squared plus left parenthesis 888 horizontal ellipsis n$ digits )=

maths-General

General

maths-

In a $increment blank P Q R$ as shown in figure given that $x colon y colon z equals 2 colon 3 colon 6$ , then the value of $angle Q P R$ is

null

equals fraction numerator fraction numerator y over denominator z end fraction plus fraction numerator x over denominator z end fraction over denominator 1 minus fraction numerator y over denominator z end fraction cross times fraction numerator x over denominator z end fraction end fraction

equals fraction numerator fraction numerator 3 over denominator 6 end fraction plus fraction numerator 2 over denominator 6 end fraction over denominator 1 minus fraction numerator 3 over denominator 6 end fraction cross times fraction numerator 2 over denominator 6 end fraction end fraction equals 1

rightwards double arrow blank alpha plus beta equals angle Q P R equals fraction numerator pi over denominator 4 end fraction

In a $increment blank P Q R$ as shown in figure given that $x colon y colon z equals 2 colon 3 colon 6$ , then the value of $angle Q P R$ is

maths-General

null

equals fraction numerator fraction numerator y over denominator z end fraction plus fraction numerator x over denominator z end fraction over denominator 1 minus fraction numerator y over denominator z end fraction cross times fraction numerator x over denominator z end fraction end fraction

equals fraction numerator fraction numerator 3 over denominator 6 end fraction plus fraction numerator 2 over denominator 6 end fraction over denominator 1 minus fraction numerator 3 over denominator 6 end fraction cross times fraction numerator 2 over denominator 6 end fraction end fraction equals 1

rightwards double arrow blank alpha plus beta equals angle Q P R equals fraction numerator pi over denominator 4 end fraction

General

physics-

A bob of mass M is suspended by a massless string of length L. The horizontal velocity $v$ at position A is just sufficient to make it reach the point B. The angle $theta$ at which the speed of the bob is half of that at A, satisfies

Velocity of the bob at the point A

v equals square root of 5 g L end root

(i)

open parentheses fraction numerator v over denominator 2 end fraction close parentheses to the power of 2 end exponent equals v to the power of 2 end exponent minus 2 g h open parentheses i i close parentheses

h equals L left parenthesis 1 minus cos invisible function application theta right parenthesis left parenthesis i i i right parenthesis

S o l v i n g blank E q s. open parentheses i close parentheses comma blank open parentheses i i close parentheses a n d blank open parentheses i i i close parentheses comma blank w e blank g e t

cos invisible function application theta equals negative fraction numerator 7 over denominator 8 end fraction

o r blank theta equals c o s to the power of negative 1 end exponent open parentheses negative fraction numerator 7 over denominator 8 end fraction close parentheses equals 151 degree

A bob of mass M is suspended by a massless string of length L. The horizontal velocity $v$ at position A is just sufficient to make it reach the point B. The angle $theta$ at which the speed of the bob is half of that at A, satisfies

physics-General

Velocity of the bob at the point A

v equals square root of 5 g L end root

(i)

open parentheses fraction numerator v over denominator 2 end fraction close parentheses to the power of 2 end exponent equals v to the power of 2 end exponent minus 2 g h open parentheses i i close parentheses

h equals L left parenthesis 1 minus cos invisible function application theta right parenthesis left parenthesis i i i right parenthesis

S o l v i n g blank E q s. open parentheses i close parentheses comma blank open parentheses i i close parentheses a n d blank open parentheses i i i close parentheses comma blank w e blank g e t

cos invisible function application theta equals negative fraction numerator 7 over denominator 8 end fraction

o r blank theta equals c o s to the power of negative 1 end exponent open parentheses negative fraction numerator 7 over denominator 8 end fraction close parentheses equals 151 degree

General

physics-

A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v subscript A end subscript comma v subscript B end subscript$ and $v subscript D end subscript$ are speed at position $A comma B$ and $D$ then

A comma blank v subscript A end subscript equals square root of g l end root

B comma blank v subscript B end subscript equals square root of 5 g l end root

and at

D comma blank v subscript D end subscript equals square root of 3 g l end root

Thus,

v subscript B end subscript greater than v subscript D end subscript greater than v subscript A end subscript

Also,

T equals 3 blank m g left parenthesis 1 plus cos invisible function application theta right parenthesis

So,

D comma theta equals 90 degree

therefore blank T equals 3 blank m g open parentheses 1 plus theta close parentheses equals 3 blank m g

A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v subscript A end subscript comma v subscript B end subscript$ and $v subscript D end subscript$ are speed at position $A comma B$ and $D$ then

physics-General

A comma blank v subscript A end subscript equals square root of g l end root

B comma blank v subscript B end subscript equals square root of 5 g l end root

and at

D comma blank v subscript D end subscript equals square root of 3 g l end root

Thus,

v subscript B end subscript greater than v subscript D end subscript greater than v subscript A end subscript

Also,

T equals 3 blank m g left parenthesis 1 plus cos invisible function application theta right parenthesis

So,

D comma theta equals 90 degree

therefore blank T equals 3 blank m g open parentheses 1 plus theta close parentheses equals 3 blank m g

General

physics-

A bob of mass $M$ is suspended by a massless string of length $L$ . The horizontal velocity $V$ at position $A$ is just sufficient to make it reach the point $B$ . The angle $theta$ at which the speed of the bob is half of that at $A$ , satisfies

V to the power of 2 end exponent equals U to the power of 2 end exponent minus 2 g left parenthesis L minus L cos invisible function application theta right parenthesis

fraction numerator 5 g L over denominator 4 end fraction equals 5 g L minus 2 g L left parenthesis 1 minus cos invisible function application theta right parenthesis

5 equals 20 minus 8 plus 8 cos invisible function application theta

cos invisible function application theta equals negative fraction numerator 7 over denominator 8 end fraction

fraction numerator 3 pi over denominator 4 end fraction less than theta less than pi

A bob of mass $M$ is suspended by a massless string of length $L$ . The horizontal velocity $V$ at position $A$ is just sufficient to make it reach the point $B$ . The angle $theta$ at which the speed of the bob is half of that at $A$ , satisfies

physics-General

V to the power of 2 end exponent equals U to the power of 2 end exponent minus 2 g left parenthesis L minus L cos invisible function application theta right parenthesis

fraction numerator 5 g L over denominator 4 end fraction equals 5 g L minus 2 g L left parenthesis 1 minus cos invisible function application theta right parenthesis

5 equals 20 minus 8 plus 8 cos invisible function application theta

cos invisible function application theta equals negative fraction numerator 7 over denominator 8 end fraction

fraction numerator 3 pi over denominator 4 end fraction less than theta less than pi

General

physics-

A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$ , what is the average acceleration in going from $A$ to $B$ ?

Here,

T equals fraction numerator 2 pi r over denominator 4 v end fraction equals fraction numerator pi r over denominator 2 v end fraction

Change in velocity is going from

A

B

v square root of 2

Average acceleration

equals fraction numerator v square root of 2 over denominator pi r divided by 2 v end fraction equals fraction numerator 2 square root of 2 v to the power of 2 end exponent over denominator pi r end fraction

A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$ , what is the average acceleration in going from $A$ to $B$ ?

physics-General

Here,

T equals fraction numerator 2 pi r over denominator 4 v end fraction equals fraction numerator pi r over denominator 2 v end fraction

Change in velocity is going from

A

B

v square root of 2

Average acceleration

equals fraction numerator v square root of 2 over denominator pi r divided by 2 v end fraction equals fraction numerator 2 square root of 2 v to the power of 2 end exponent over denominator pi r end fraction

General

physics-

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

R = \frac{u^{2} \sin 2 θ}{g} = \frac{2 u_{x} v_{y}}{g}

∴

Range

\propto

horizontal initial velocity

(u_{x})

In path 4 range is maximum so football possess maximum horizontal velocity in the path

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

physics-General

R = \frac{u^{2} \sin 2 θ}{g} = \frac{2 u_{x} v_{y}}{g}

∴

Range

\propto

horizontal initial velocity

(u_{x})

In path 4 range is maximum so football possess maximum horizontal velocity in the path

General

physics-

A boy throws a cricket ball from the boundary to the wicket-keeper. If the frictional force due to air cannot be ignored, the forces acting on the ball at the position X are respected by

The forces acting on the ball will be (i) in the direction opposite to its motion

i e,

frictional force and(ii) weight

m g

A boy throws a cricket ball from the boundary to the wicket-keeper. If the frictional force due to air cannot be ignored, the forces acting on the ball at the position X are respected by

physics-General

The forces acting on the ball will be (i) in the direction opposite to its motion

i e,

frictional force and(ii) weight

m g

General

physics-

A projectile $A$ is thrown at an angle of $30 °$ to the horizontal from point $P$ . At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A, \frac{v_{2}}{v_{1}}$ should be

Equating velocities along the vertical,

v_{2} = v_{1} \sin 30 ° o r \frac{v_{2}}{v_{1}} = \frac{1}{2}

A projectile $A$ is thrown at an angle of $30 °$ to the horizontal from point $P$ . At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A, \frac{v_{2}}{v_{1}}$ should be

physics-General

Equating velocities along the vertical,

v_{2} = v_{1} \sin 30 ° o r \frac{v_{2}}{v_{1}} = \frac{1}{2}

General

physics-

In a two dimensional motion of a particle, the particle moves from point $A$ , position vector $stack r with rightwards arrow on top subscript 1 end subscript$ . If the magnitudes of these vectors are respectively, $r subscript 1 end subscript$ =3 and $r subscript 2 end subscript equals 4$ and the angles they make with the $x$ -axis are $theta subscript 1 end subscript equals 75 degree$ and 15 $degree$ , respectively, then find the magnitude of the displacement vector

Displacement

equals A B

angle between

stack r subscript 1 end subscript with rightwards arrow on top

and

stack r subscript 2 end subscript with rightwards arrow on top

theta equals 75 degree minus 15 degree equals 60 degree

From figure

A B to the power of 2 end exponent equals r subscript 1 end subscript superscript 2 end superscript plus r subscript 2 end subscript superscript 2 end superscript minus 2 r subscript 1 end subscript r subscript 2 end subscript c o s theta

equals 3 to the power of 2 end exponent plus 4 to the power of 2 end exponent minus 2 cross times 3 cross times 4

cos

60 degree

equals 13

A B equals square root of 13

In a two dimensional motion of a particle, the particle moves from point $A$ , position vector $stack r with rightwards arrow on top subscript 1 end subscript$ . If the magnitudes of these vectors are respectively, $r subscript 1 end subscript$ =3 and $r subscript 2 end subscript equals 4$ and the angles they make with the $x$ -axis are $theta subscript 1 end subscript equals 75 degree$ and 15 $degree$ , respectively, then find the magnitude of the displacement vector

physics-General

Displacement

equals A B

angle between

stack r subscript 1 end subscript with rightwards arrow on top

and

stack r subscript 2 end subscript with rightwards arrow on top

theta equals 75 degree minus 15 degree equals 60 degree

From figure

A B to the power of 2 end exponent equals r subscript 1 end subscript superscript 2 end superscript plus r subscript 2 end subscript superscript 2 end superscript minus 2 r subscript 1 end subscript r subscript 2 end subscript c o s theta

equals 3 to the power of 2 end exponent plus 4 to the power of 2 end exponent minus 2 cross times 3 cross times 4

cos

60 degree

equals 13

A B equals square root of 13

General

physics-

A particle is moving on a circular path of radius $r$ with uniform velocity $v$ . The change in velocity when the particle moves from $P blank$ to $blank Q blank$ is $blank left parenthesis angle P O Q equals 40 degree right parenthesis$

Change in velocity

equals 2 v sin invisible function application open parentheses theta divided by 2 close parentheses equals 2 v sin invisible function application 20 degree

A particle is moving on a circular path of radius $r$ with uniform velocity $v$ . The change in velocity when the particle moves from $P blank$ to $blank Q blank$ is $blank left parenthesis angle P O Q equals 40 degree right parenthesis$

physics-General

Change in velocity

equals 2 v sin invisible function application open parentheses theta divided by 2 close parentheses equals 2 v sin invisible function application 20 degree

General

physics-

A fighter plane enters inside the enemy territory, at time $t equals 0$ with velocity $v subscript 0 end subscript equals 250 blank m s to the power of negative 1 end exponent$ and moves horizontally with constant acceleration $a equals 20 m s to the power of negative 2 end exponent$ (see figure). An enemy tank at the border, spot the plane and fire shots at an angle $theta equals 60 degree$ with the horizontal and with velocity $u equals 600 blank m s to the power of negative 1 end exponent$ . At what altitude $H$ of the plane it can be hit by the shot?

If it is being hit then

d equals v subscript 0 end subscript t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent equals left parenthesis u cos invisible function application theta right parenthesis t

t equals fraction numerator u cos invisible function application theta minus v subscript 0 end subscript over denominator a divided by 2 end fraction

therefore blank t equals fraction numerator 600 cross times fraction numerator 1 over denominator 2 end fraction minus 250 over denominator 10 end fraction equals 5 blank s

H equals open parentheses u sin invisible function application theta close parentheses t minus fraction numerator 1 over denominator 2 end fraction cross times g t to the power of 2 end exponent

equals 600 cross times fraction numerator square root of 3 over denominator 2 end fraction cross times 5 minus fraction numerator 1 over denominator 2 end fraction cross times 10 cross times 25

H equals 2473 blank m

A fighter plane enters inside the enemy territory, at time $t equals 0$ with velocity $v subscript 0 end subscript equals 250 blank m s to the power of negative 1 end exponent$ and moves horizontally with constant acceleration $a equals 20 m s to the power of negative 2 end exponent$ (see figure). An enemy tank at the border, spot the plane and fire shots at an angle $theta equals 60 degree$ with the horizontal and with velocity $u equals 600 blank m s to the power of negative 1 end exponent$ . At what altitude $H$ of the plane it can be hit by the shot?

physics-General

If it is being hit then

d equals v subscript 0 end subscript t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent equals left parenthesis u cos invisible function application theta right parenthesis t

t equals fraction numerator u cos invisible function application theta minus v subscript 0 end subscript over denominator a divided by 2 end fraction

therefore blank t equals fraction numerator 600 cross times fraction numerator 1 over denominator 2 end fraction minus 250 over denominator 10 end fraction equals 5 blank s

H equals open parentheses u sin invisible function application theta close parentheses t minus fraction numerator 1 over denominator 2 end fraction cross times g t to the power of 2 end exponent

equals 600 cross times fraction numerator square root of 3 over denominator 2 end fraction cross times 5 minus fraction numerator 1 over denominator 2 end fraction cross times 10 cross times 25

H equals 2473 blank m

General

physics-

From an inclined plane two particles are projected with same speed at same angle $theta$ , one up and other down the plane as shown in figure, which of the following statements is/are correct?

H e r e comma blank alpha equals 2 theta comma blank beta equals theta

T i m e blank o f blank f l i g h t blank o f blank A blank i s comma

T subscript 1 end subscript equals fraction numerator 2 u sin invisible function application open parentheses alpha minus beta close parentheses over denominator g cos invisible function application beta end fraction

equals fraction numerator 2 u sin invisible function application open parentheses 2 theta minus theta close parentheses over denominator g cos invisible function application theta end fraction

equals fraction numerator 2 u over denominator g end fraction tan invisible function application theta

T i m e blank o f blank f l i g h t blank o f blank B blank i s comma blank T subscript 2 end subscript equals fraction numerator 2 u sin invisible function application theta over denominator g cos invisible function application theta end fraction

equals fraction numerator 2 u over denominator g end fraction tan invisible function application theta

So,

T subscript 1 end subscript equals T subscript 2 end subscript

. The acceleration of both the particles is

g

downwards. Therefore, relative acceleration between the two I zero or relative motion between the two is uniform. The relative velocity of

A

w.r.t.

B

is towards

A B

, therefore collision will take place between the two in mid air.

From an inclined plane two particles are projected with same speed at same angle $theta$ , one up and other down the plane as shown in figure, which of the following statements is/are correct?

physics-General

H e r e comma blank alpha equals 2 theta comma blank beta equals theta

T i m e blank o f blank f l i g h t blank o f blank A blank i s comma

T subscript 1 end subscript equals fraction numerator 2 u sin invisible function application open parentheses alpha minus beta close parentheses over denominator g cos invisible function application beta end fraction

equals fraction numerator 2 u sin invisible function application open parentheses 2 theta minus theta close parentheses over denominator g cos invisible function application theta end fraction

equals fraction numerator 2 u over denominator g end fraction tan invisible function application theta

T i m e blank o f blank f l i g h t blank o f blank B blank i s comma blank T subscript 2 end subscript equals fraction numerator 2 u sin invisible function application theta over denominator g cos invisible function application theta end fraction

equals fraction numerator 2 u over denominator g end fraction tan invisible function application theta

So,

T subscript 1 end subscript equals T subscript 2 end subscript

. The acceleration of both the particles is

g

downwards. Therefore, relative acceleration between the two I zero or relative motion between the two is uniform. The relative velocity of

A

w.r.t.

B

is towards

A B

, therefore collision will take place between the two in mid air.

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The ultimate source of organic evolution is

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Sexual reproduction
Hormonal action
Mutations

Answer:The correct answer is: Mutations

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Related Questions to study

The sum of all integers between 50 and 500 which are divisible by 7 is

The sum of all integers between 50 and 500 which are divisible by 7 is

$left parenthesis 666 horizontal ellipsis text n digits end text right parenthesis squared plus left parenthesis 888 horizontal ellipsis n$ digits )=

$left parenthesis 666 horizontal ellipsis text n digits end text right parenthesis squared plus left parenthesis 888 horizontal ellipsis n$ digits )=

In a $increment blank P Q R$ as shown in figure given that $x colon y colon z equals 2 colon 3 colon 6$ , then the value of $angle Q P R$ is

In a $increment blank P Q R$ as shown in figure given that $x colon y colon z equals 2 colon 3 colon 6$ , then the value of $angle Q P R$ is

A bob of mass M is suspended by a massless string of length L. The horizontal velocity $v$ at position A is just sufficient to make it reach the point B. The angle $theta$ at which the speed of the bob is half of that at A, satisfies

A bob of mass M is suspended by a massless string of length L. The horizontal velocity $v$ at position A is just sufficient to make it reach the point B. The angle $theta$ at which the speed of the bob is half of that at A, satisfies

A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v subscript A end subscript comma v subscript B end subscript$ and $v subscript D end subscript$ are speed at position $A comma B$ and $D$ then

A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v subscript A end subscript comma v subscript B end subscript$ and $v subscript D end subscript$ are speed at position $A comma B$ and $D$ then

A bob of mass $M$ is suspended by a massless string of length $L$ . The horizontal velocity $V$ at position $A$ is just sufficient to make it reach the point $B$ . The angle $theta$ at which the speed of the bob is half of that at $A$ , satisfies

A bob of mass $M$ is suspended by a massless string of length $L$ . The horizontal velocity $V$ at position $A$ is just sufficient to make it reach the point $B$ . The angle $theta$ at which the speed of the bob is half of that at $A$ , satisfies

A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$ , what is the average acceleration in going from $A$ to $B$ ?

A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$ , what is the average acceleration in going from $A$ to $B$ ?

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

A boy throws a cricket ball from the boundary to the wicket-keeper. If the frictional force due to air cannot be ignored, the forces acting on the ball at the position X are respected by

A boy throws a cricket ball from the boundary to the wicket-keeper. If the frictional force due to air cannot be ignored, the forces acting on the ball at the position X are respected by

A projectile $A$ is thrown at an angle of $30 °$ to the horizontal from point $P$ . At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A, \frac{v_{2}}{v_{1}}$ should be

A projectile $A$ is thrown at an angle of $30 °$ to the horizontal from point $P$ . At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A, \frac{v_{2}}{v_{1}}$ should be

A particle is moving on a circular path of radius $r$ with uniform velocity $v$ . The change in velocity when the particle moves from $P blank$ to $blank Q blank$ is $blank left parenthesis angle P O Q equals 40 degree right parenthesis$

A particle is moving on a circular path of radius $r$ with uniform velocity $v$ . The change in velocity when the particle moves from $P blank$ to $blank Q blank$ is $blank left parenthesis angle P O Q equals 40 degree right parenthesis$

From an inclined plane two particles are projected with same speed at same angle $theta$ , one up and other down the plane as shown in figure, which of the following statements is/are correct?

From an inclined plane two particles are projected with same speed at same angle $theta$ , one up and other down the plane as shown in figure, which of the following statements is/are correct?

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The ultimate source of organic evolution is

Natural selection Sexual reproduction Hormonal action Mutations

Answer:The correct answer is: Mutations

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Related Questions to study

If are in A.P with common difference then sind terms]

If are in A.P with common difference then sind terms]

The sum of all integers between 50 and 500 which are divisible by 7 is

The sum of all integers between 50 and 500 which are divisible by 7 is

digits )=

digits )=

In a as shown in figure given that , then the value of is

In a as shown in figure given that , then the value of is

A bob of mass M is suspended by a massless string of length L. The horizontal velocity at position A is just sufficient to make it reach the point B. The angle at which the speed of the bob is half of that at A, satisfies

A bob of mass M is suspended by a massless string of length L. The horizontal velocity at position A is just sufficient to make it reach the point B. The angle at which the speed of the bob is half of that at A, satisfies

A particle of mass attracted with a string of length is just revolving on the vertical circle without slacking of the string. If and are speed at position and then

A particle of mass attracted with a string of length is just revolving on the vertical circle without slacking of the string. If and are speed at position and then

A bob of mass is suspended by a massless string of length . The horizontal velocity at position is just sufficient to make it reach the point . The angle at which the speed of the bob is half of that at , satisfies

A bob of mass is suspended by a massless string of length . The horizontal velocity at position is just sufficient to make it reach the point . The angle at which the speed of the bob is half of that at , satisfies

A body of mass is moving with a uniform speed along a circle of radius , what is the average acceleration in going from to ?

A body of mass is moving with a uniform speed along a circle of radius , what is the average acceleration in going from to ?

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

A boy throws a cricket ball from the boundary to the wicket-keeper. If the frictional force due to air cannot be ignored, the forces acting on the ball at the position X are respected by

A boy throws a cricket ball from the boundary to the wicket-keeper. If the frictional force due to air cannot be ignored, the forces acting on the ball at the position X are respected by

A projectile A is thrown at an angle of 30° to the horizontal from point P. At the same time, another projectile B is thrown with velocity v2 upwards from the point Q vertically below the highest point. For B to collide with A, v2v1 should be

A projectile A is thrown at an angle of 30° to the horizontal from point P. At the same time, another projectile B is thrown with velocity v2 upwards from the point Q vertically below the highest point. For B to collide with A, v2v1 should be

In a two dimensional motion of a particle, the particle moves from point , position vector . If the magnitudes of these vectors are respectively, =3 and and the angles they make with the -axis are and 15, respectively, then find the magnitude of the displacement vector

In a two dimensional motion of a particle, the particle moves from point , position vector . If the magnitudes of these vectors are respectively, =3 and and the angles they make with the -axis are and 15, respectively, then find the magnitude of the displacement vector

A particle is moving on a circular path of radius with uniform velocity . The change in velocity when the particle moves from tois

A particle is moving on a circular path of radius with uniform velocity . The change in velocity when the particle moves from tois

From an inclined plane two particles are projected with same speed at same angle , one up and other down the plane as shown in figure, which of the following statements is/are correct?

From an inclined plane two particles are projected with same speed at same angle , one up and other down the plane as shown in figure, which of the following statements is/are correct?

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Natural selection
Sexual reproduction
Hormonal action
Mutations

$left parenthesis 666 horizontal ellipsis text n digits end text right parenthesis squared plus left parenthesis 888 horizontal ellipsis n$ digits )=

$left parenthesis 666 horizontal ellipsis text n digits end text right parenthesis squared plus left parenthesis 888 horizontal ellipsis n$ digits )=

In a $increment blank P Q R$ as shown in figure given that $x colon y colon z equals 2 colon 3 colon 6$ , then the value of $angle Q P R$ is

In a $increment blank P Q R$ as shown in figure given that $x colon y colon z equals 2 colon 3 colon 6$ , then the value of $angle Q P R$ is

A bob of mass M is suspended by a massless string of length L. The horizontal velocity $v$ at position A is just sufficient to make it reach the point B. The angle $theta$ at which the speed of the bob is half of that at A, satisfies

A bob of mass M is suspended by a massless string of length L. The horizontal velocity $v$ at position A is just sufficient to make it reach the point B. The angle $theta$ at which the speed of the bob is half of that at A, satisfies

A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v subscript A end subscript comma v subscript B end subscript$ and $v subscript D end subscript$ are speed at position $A comma B$ and $D$ then

A particle of mass $m$ attracted with a string of length $l$ is just revolving on the vertical circle without slacking of the string. If $v subscript A end subscript comma v subscript B end subscript$ and $v subscript D end subscript$ are speed at position $A comma B$ and $D$ then

A bob of mass $M$ is suspended by a massless string of length $L$ . The horizontal velocity $V$ at position $A$ is just sufficient to make it reach the point $B$ . The angle $theta$ at which the speed of the bob is half of that at $A$ , satisfies

A bob of mass $M$ is suspended by a massless string of length $L$ . The horizontal velocity $V$ at position $A$ is just sufficient to make it reach the point $B$ . The angle $theta$ at which the speed of the bob is half of that at $A$ , satisfies

A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$ , what is the average acceleration in going from $A$ to $B$ ?

A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$ , what is the average acceleration in going from $A$ to $B$ ?

A projectile $A$ is thrown at an angle of $30 °$ to the horizontal from point $P$ . At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A, \frac{v_{2}}{v_{1}}$ should be

A projectile $A$ is thrown at an angle of $30 °$ to the horizontal from point $P$ . At the same time, another projectile $B$ is thrown with velocity $v^{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A, \frac{v_{2}}{v_{1}}$ should be

A particle is moving on a circular path of radius $r$ with uniform velocity $v$ . The change in velocity when the particle moves from $P blank$ to $blank Q blank$ is $blank left parenthesis angle P O Q equals 40 degree right parenthesis$

A particle is moving on a circular path of radius $r$ with uniform velocity $v$ . The change in velocity when the particle moves from $P blank$ to $blank Q blank$ is $blank left parenthesis angle P O Q equals 40 degree right parenthesis$

From an inclined plane two particles are projected with same speed at same angle $theta$ , one up and other down the plane as shown in figure, which of the following statements is/are correct?

From an inclined plane two particles are projected with same speed at same angle $theta$ , one up and other down the plane as shown in figure, which of the following statements is/are correct?