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In first transition series, the melting point of M n is low because

  1. Due to d to the power of 10 end exponent configuration, metallic bonds are strong    
  2. Due to d to the power of 7 end exponent configuration, metallic bonds are weak    
  3. Due to d to the power of 5 end exponent configuration, metallic bonds are weak    
  4. None of these    

The correct answer is: Due to d to the power of 5 end exponent configuration, metallic bonds are weak


    Due to d to the power of 5 end exponent configuration, metallic bonds are weak. d to the power of 5 end exponent orbital is half filled as a result 3 d electrons are more tightly held by the nucleus and this reduces the de-localization of electrons resulting in weaker metallic bonding.

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