General
Easy
Chemistry-

Which one of the following will be the major product when

Is treated with dilute H2SO4 in the presence of HgSO4

Chemistry-General

  1.    
  2.    
  3.    
  4.    

    Answer:The correct answer is:

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    Transformation of C = O group into CH2 in the presence of Zn + Hg is called Clemmensen’s reduction and in the presence of NH2 - NH2/OH- is called Wolf-Kishner Reduction
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    For the given uniform square lamina A B C D, whose centre is O

    Let the each side of square lamina is d.
    So, I subscript E F end subscript equals I subscript G H end subscript (due to symmetry)
    And I subscript A C end subscript equals I subscript B D end subscript (due to symmetry)
    Now, according to theorem of perpendicular axis,

    I subscript A C end subscript plus I subscript B D end subscript equals I subscript 0 end subscript
    rightwards double arrow 2 I subscript A C end subscript equals I subscript 0 end subscript (i)
    and I subscript E F end subscript plus I subscript G H end subscript equals I subscript 0 end subscript
    rightwards double arrow 2 I subscript E F end subscript equals I subscript 0 end subscript (ii)
    From Eqs. (i) and (ii), we get
    I subscript A C end subscript equals I subscript E F end subscript
    therefore I subscript A D end subscript equals I subscript E F end subscript plus fraction numerator m d to the power of 2 end exponent over denominator 4 end fraction
    equals fraction numerator m d to the power of 2 end exponent over denominator 12 end fraction plus fraction numerator m d to the power of 2 end exponent over denominator 4 end fraction open parentheses a s I subscript E F end subscript equals fraction numerator m d to the power of 2 end exponent over denominator 12 end fraction close parentheses
    So, I subscript A D end subscript equals fraction numerator m d to the power of 2 end exponent over denominator 3 end fraction equals 4 I subscript E F end subscript

    For the given uniform square lamina A B C D, whose centre is O

    physics-General
    Let the each side of square lamina is d.
    So, I subscript E F end subscript equals I subscript G H end subscript (due to symmetry)
    And I subscript A C end subscript equals I subscript B D end subscript (due to symmetry)
    Now, according to theorem of perpendicular axis,

    I subscript A C end subscript plus I subscript B D end subscript equals I subscript 0 end subscript
    rightwards double arrow 2 I subscript A C end subscript equals I subscript 0 end subscript (i)
    and I subscript E F end subscript plus I subscript G H end subscript equals I subscript 0 end subscript
    rightwards double arrow 2 I subscript E F end subscript equals I subscript 0 end subscript (ii)
    From Eqs. (i) and (ii), we get
    I subscript A C end subscript equals I subscript E F end subscript
    therefore I subscript A D end subscript equals I subscript E F end subscript plus fraction numerator m d to the power of 2 end exponent over denominator 4 end fraction
    equals fraction numerator m d to the power of 2 end exponent over denominator 12 end fraction plus fraction numerator m d to the power of 2 end exponent over denominator 4 end fraction open parentheses a s I subscript E F end subscript equals fraction numerator m d to the power of 2 end exponent over denominator 12 end fraction close parentheses
    So, I subscript A D end subscript equals fraction numerator m d to the power of 2 end exponent over denominator 3 end fraction equals 4 I subscript E F end subscript
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    I equals open square brackets fraction numerator 2 over denominator 5 end fraction cross times 1 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 1 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
    plus open square brackets fraction numerator 2 over denominator 5 end fraction cross times 2 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 2 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
    plus open square brackets fraction numerator 2 over denominator 5 end fraction cross times 3 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 3 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
    plus open square brackets fraction numerator 2 over denominator 5 end fraction cross times 4 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 4 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
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    I equals open square brackets fraction numerator 2 over denominator 5 end fraction cross times 1 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 1 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
    plus open square brackets fraction numerator 2 over denominator 5 end fraction cross times 2 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 2 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
    plus open square brackets fraction numerator 2 over denominator 5 end fraction cross times 3 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 3 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
    plus open square brackets fraction numerator 2 over denominator 5 end fraction cross times 4 cross times open parentheses 0.1 close parentheses to the power of 2 end exponent plus 4 cross times open parentheses 1 close parentheses to the power of 2 end exponent close square brackets
    equals 1.004 plus 2.008 plus 3.012 plus 4.016
    equals 10.04 blank k g minus m to the power of 2 end exponent
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