Question

# Find the area of an isosceles trapezium ABCD, if the parallel sides are 6cm and 14 cm, its non parallel sides is 5cm each.

Hint:

### Draw the parallel line from C parallel to AD which cuts the AB at E .

We get a triangle and parallelogram. we find the area of triangle in both heron's

method and using formula area = ½ b × h and equating we get height h

Now , find the area of Trapezium = ½ height × (sum of lengths of parallel sides).

## The correct answer is: 30 cm2

### Ans :- 30 cm^{2}.

Explanation :-

Step 1:- Given lengths of parallel sides is 6 and 14 cm .

Length of non parallel sides is 5 and 5 cm

We get a triangle and parallelogram ABED

we get CE = 5 cm ; AE = 6 cm (opposites sides of parallelogram )

BE = BA-AE = 14- 6 = 8 cm .

Step 2:- Equate the areas and find value of height h

Step 3:-Find the area of trapezium

Therefore, Area of trapezium ABCD = 30 cm^{2}.

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Celsius , on the horizontal axis, and the pressure p , in gigapascals (G Pa), on the

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**Note:**

We do not have the exact inequalities in the option, so we choose the one from the options which is the closest approximation of the inequalities that we have calculated. There are a couple of formulas and concepts used here, such as the equation of a line passing through two points and the concept that the region below a line is given by replacing the equality sign with less than or equal to in the standard form of the equation and vice versa.

During mineral formation, the same chemical compound can be come different minerals depending on the temperature and pressure at the time of formation. A phase diagram is a graph that shows the conditions that are needed to form each mineral. The graph above is a portion of the phase diagram for aluminosilicates, with the temperature t , in degrees

Celsius , on the horizontal axis, and the pressure p , in gigapascals (G Pa), on the

Which of the following systems of inequalities best describes the region where sillimanite can form?

**Note:**

We do not have the exact inequalities in the option, so we choose the one from the options which is the closest approximation of the inequalities that we have calculated. There are a couple of formulas and concepts used here, such as the equation of a line passing through two points and the concept that the region below a line is given by replacing the equality sign with less than or equal to in the standard form of the equation and vice versa.